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statuscvo [17]
4 years ago
7

Marcs is growing three bean plants as part of a science experiment. Plant A 1/3 inch tall. Plant B is 3/4 inch tall. Plant C is

5/6 inch tall. Order the plants from shortest to tallest.
Mathematics
2 answers:
snow_tiger [21]4 years ago
8 0
Shortest to tallest: Plant A, Plant B, Plant C.

Given:
Plant A 1/3 inch tall
Plant B 3/4 inch tall
Plant C 5/6 inch tall

Order from shortest to tallest.

First we need to get the least common multiple of the three fractions.

Multiple of 3: 3, 6, 9, 12
Multiple of 4: 4, 8, 12, 16
Multiple of 6: 6, 12, 18

Their least common multiple is 12. We need to multiply each fraction by the number that will give the product of 12 to the denominator.

Plant A: 1/3 * 4/4 =   4/12
Plant B: 3/4 * 3/3 =   9/12
Plant C: 5/6 * 2/2 = 10/12

Since the denominator is common, we will use the numerator as basis in ordering the plants from shortest to tallest. 

4 is less than 9 and 9 is less than 10.

so, Plant A is the shortest, Plant B is the medium height, and Plant C is the tallest.
NemiM [27]4 years ago
4 0
1/3 , 3/4, 5/6

1÷3= <span>0.333333

3</span>÷4= 0.75

5÷6= 0.8333333333333333

Hope I This Helps :D
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