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mojhsa [17]
3 years ago
12

A pizza has a 14-inch diameter. What is the approximate area of the pizza? USE 3.14 for π.

Mathematics
2 answers:
REY [17]3 years ago
7 0

Answer:

Step-by-step explanation:

How approximate is approximate?

I'll give you an answer to 2 decimal places.

Area = pi * r^2

r = d/2

d = 14

r = 14/2

r = 7

Area = 3.14 * 7^2

Area = 3.14 * 49

Area = 153.86 sq in.

Lots of pizza! Enjoy!

Llana [10]3 years ago
5 0

Answer:

A≈153.94

Step-by-step explanation:

A=πr2=π·72≈153.93804

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Which of the following is not a step in the procedure for​ two-way ANOVA to test for an interaction​ effect, an effect from the
vovikov84 [41]

Answer:

D. If the​ P-value is​ large, reject the null hypothesis of no interaction. Conclude that there is an interaction effect.

Step-by-step explanation:

If p value is smaller than significant level(5% or 1%), then reject the null hypothesis.

From the given information about two way ANOVA, First 3 are true statements based on decision rule.

4th statement is false, becasue p value is larger, then decision is to fail the null hypothesis and conclude that there is no interaction between them

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3 years ago
A water balloon is catapulted into the air so that it's height, in meters, after t seconds is h = -4.9t^ +27t +2.4
zysi [14]
h = -4..9t^2+27t+2.4\ for\ t=3

Just replace t with 3 and solve.

h = -4.9*3^2 + 27*3 + 2.4 \\ h = -4.9*9 + 27*3 + 2.4 \\ h=-44.1 + 81 + 2.4 \\ \boxed{h=39.3}
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4 years ago
1) work out the value of (1.7x10^4)x (8.5x10^-2) give your answer in standard form.
Mashutka [201]

ANSWER TO QUESTION 1

(1.7\times 10^4)\times(8.5\times 10^{-2})


We rewrite to obtain;


(1.7\times 10^4)\times(8.5\times 10^{-2})=(1.7\times 8.5)\times(10^4\times 10^{-2})


Recall this product law of indices


a^m\times a^n=a^{m+n}


we apply this law to obtain,


(1.7\times 10^4)\times(8.5\times 10^{-2})=14.45\times10^{4+-2}



This simplifies to


(1.7\times 10^4)\times(8.5\times 10^{-2})=14.45\times10^{2}


We need to rewrite this in standard form;


(1.7\times 10^4)\times(8.5\times 10^{-2})=1.445\times 10^1\times10^{2}


We apply the product law again to get


(1.7\times 10^4)\times(8.5\times 10^{-2})=1.445\times 10^{1+2}


This simplifies to

(1.7\times 10^4)\times(8.5\times 10^{-2})=1.445\times 10^{3}



ANSWER TO QUESTION 2


(6.8\times 10^2)\times(1.3\times 10^{-3})


We rewrite to obtain;


(6.8\times 10^2)\times(1.3\times 10^-3)=(6.8\times 1.3)\times(10^2\times 10^{-3})


Recall this product law of indices


a^m\times a^n=a^{m+n}


we apply this law to obtain,


(6.8\times 10^2)\times(1.3\times 10^-3)=8.84\times10^{2+-3}



This simplifies to


(6.8\times 10^2)\times(1.3\times 10^-3)=8.84\times10^{-1}


This is already in standard form.







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3 years ago
Help! what is the surface area of the figure?
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Answer:

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Step-by-step explanation:

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