That is an interactive question.
Answer:
In C++:
#include <bits/stdc++.h>
#include <iostream>
#include <vector>
using namespace std;
int main(){
vector<int> vectItems;
cout << "Vector length: ";
int ln; cin>>ln;
int num;
for (int ikk = 0; ikk < ln; ikk++){
cin >> num;
vectItems.push_back(num);}
int small, secsmall;
small = secsmall = INT_MAX;
for (int ikk = 0; ikk < ln; ikk++){
if(vectItems[ikk] < small){
secsmall = small;
small = vectItems[ikk]; }
else if (vectItems[ikk] < secsmall && vectItems[ikk] != small) {
secsmall = vectItems[ikk];} }
cout<<small<<" "<<secsmall;
return 0;}
Explanation:
See attachment for program file where comments are used for explanation
Cryptographic system converts between plaintext and ciphertext. Cryptography is t<span>he process of making and using codes to secure transmission of information.
The c</span>ryptographic system involves encryption (the process of converting original message into a form unreadable by unauthorized individuals) and decryption (t<span>he process of converting the cipher text message back into plaintext so that it can be readily understood.)</span>
=(Happy)&(Birthday) this is how it would be formatted
Answer:
public static int maxMagnitude(int a, int b){
int max;
if (a>b){
max = a;
}
else{
max = b;
}
return max;
}
The complete program calling the method is given in the explanation section
Explanation:
import java.util.Scanner;
public class ANot {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Please Enter two numbers");
int num1= in.nextInt();
int num2 = in.nextInt();
System.out.println("The largest magnitude number is: "+maxMagnitude(num1,num2));
}
public static int maxMagnitude(int a, int b){
int max;
if (a>b){
max = a;
}
else{
max = b;
}
return max;
}
}
The maxMagnitude() method uses if/else statement to compare two ints and return the larger one
