Suppose a baby food company has determined that its total revenue R for its food is given by R = − x 3 + 39 x 2 + 945 x where R
is measured in dollars and x is the number of units (in thousands) produced. What production level will yield a maximum revenue?
1 answer:
Answer:
35,000 units
Step-by-step explanation:
Total revenue is:
![R = -x^3+39x^2+945x](https://tex.z-dn.net/?f=R%20%3D%20-x%5E3%2B39x%5E2%2B945x)
The maximum revenue is attained at the production level for which the derivate of the revenue function is zero:
![R = -x^3+39x^2+945x\\R'=0=-3x^2+78x+945\\x=\frac{-b\pm\sqrt{78^2-(4*(-3)*945)} }{-6}\\x_1=35\\x_2=-9](https://tex.z-dn.net/?f=R%20%3D%20-x%5E3%2B39x%5E2%2B945x%5C%5CR%27%3D0%3D-3x%5E2%2B78x%2B945%5C%5Cx%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7B78%5E2-%284%2A%28-3%29%2A945%29%7D%20%7D%7B-6%7D%5C%5Cx_1%3D35%5C%5Cx_2%3D-9)
Since production cannot be negative, revenue will be at a maximum when x = 35, or when the production level is 35,000 units.
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