Evaluate y^2 = x for x = 121 a. y = 11 b. y = -11 c. y = +=11 d. y = 121

Which value makes the equation 2x -4 = 16 true? *

Alinara [238K]

Answer:

10 makes this equation true

Step-by-step explanation:

2x -4 = 16 /+4

2x= 20 /÷2

x= 10

Test

2(10) - 4 = 16

20 - 4 = 16 Correct

4 0

3 years ago

Read 2 more answers

A pair of equations is shown below:

kati45 [8]

This kinda took a lot of effort but hope it helps

4 0

3 years ago

Read 2 more answers

Solve using Fourier series.

Olin [163]

With $2L=\pi$ , the Fourier series expansion of $f(x)$ is

$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L$
$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx$

where the coefficients are obtained by computing

$\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx$
$\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx$

$\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx$

$\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx$

You should end up with

$a_0=0$
$a_n=0$
(both due to the fact that $f(x)$ is odd)
$b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)$

Now the problem is that this expansion does not match the given one. As a matter of fact, since $f(x)$ is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of $f(x)$ , which is to say we're actually considering the function

$\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3$

and enforcing a period of $2L=2\pi$ . Now, you should find that

$\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)$

The value of the sum can then be verified by choosing $x=0$ , which gives

$\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)$
$\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots$

as required.

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%20x%2B%5Cfrac%7B1%7D%7B2%7D%20%3D%5Cfrac%7B3%7D%7B4%7D" id="TexFormula1"

kotegsom [21]

Answer:

$x = \frac{5}{8}$

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

6 0

3 years ago

47.9 less than k is -21.6

Law Incorporation [45]

K is equal to -69.5 K=69.5 You put it in an equation 47.9-K=-21.6Then you subtract 47.9 from both sides and you get K=69.5

3 0

4 years ago