Answer: 12 in. by 10 in.
Step-by-step explanation:
Given: The dimensions of photo is 10 in. by 8 in.
Therefore, Area of photo= 
Area of frame with photo=120 square inches
Let x be the width of the frame, then we have
Length of frame with photo= 10+2x inches
Width of frame with photo =8+2x inches
Now, 
![80+16x+20x+4x^2=120\\\Rightarrow\ 4x^2+36x-40=0\\\Rightarrowx^2+9x-10=0\\\(x-1)(x+10)=0\\\Rightarrow\ x=1,...........[text{Since length can not be negative so it cannot be -10}]](https://tex.z-dn.net/?f=80%2B16x%2B20x%2B4x%5E2%3D120%5C%5C%5CRightarrow%5C%204x%5E2%2B36x-40%3D0%5C%5C%5CRightarrowx%5E2%2B9x-10%3D0%5C%5C%5C%28x-1%29%28x%2B10%29%3D0%5C%5C%5CRightarrow%5C%20x%3D1%2C...........%5Btext%7BSince%20length%20can%20not%20be%20negative%20so%20it%20cannot%20be%20-10%7D%5D)
Thus, dimension of frame = 
Answer:
The graph is attached Below and the plotting is given below.
Step-by-step explanation:
Given:
-9x + 6y = 18
Solution:
To draw a line on a graph the required minimum two points but here we will have three points as point A, point B, and point C.
For point A
Put x = -4 in the given equation we get
-9×-4 + 6y = 18
6y = 18-36
∴ 
∴ Point A ≡ ( -4, -3 ).
For point B
Put x = -2 in the given equation we get
-9×-2 + 6y = 18
6y = 18 - 18
6y = 0
∴ 
∴ Point B ≡ ( -2, 0 ).
For point C
Put x = 0 in the given equation we get
-9×0 + 6y = 18
6y = 18
∴ 
∴ Point C ≡ ( 0, 3 ).
Now we have Point A ,B and C join it and you will have Line.
The answer is X=2 and y=-3
Y=3/4(8)-5
y=24/4-5
y=6-5
y=1