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3 years ago

What is the solution to the system of equations? HELP

Mathematics

2 answers:

notsponge [240]3 years ago

4 0

I will solve your system by substitution.x=−2;y=23x+3Step: Solvex=−2for x:Step: Substitute−2forxiny=23x+3:y=23x+3y=23(−2)+3y=53(Simplify both sides of the equation)

Answer:x=−2 and y=5/3

so the answer is B (the second choice)
(Hope it helped ^_^)

Soloha48 [4]3 years ago

3 0

The answer would be "B"

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3 years ago

Please help, I’ll mark your answer as brainliest!

statuscvo [17]

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$(x-230)^2+(y-220)^2=6100$

Step-by-step explanation:

The equation for a circle is $(x-h)^2+(y-k)^2=r^2$ , where $(h,k)$ is the vertex of the circle and $r$ is the radius. Immediately, since the center of the circle is given, we know what $h$ and $k$ are. $h$ is 230 and $k$ is 220.

The only thing we need to find is the radius, which will just be the distance from the center (230,220) to a point on the circumference (170,170). The distance between them can be calculated using the distance formula, which is really just the Pythagorean Theorem rearranged. The formula states that $d=\sqrt{x^2+y^2}$ , where $x$ is the change in the x-coordinates of the two points and $y$ is the change in the y-coordinates of the two points. Plug-in $x$ for 60 and $y$ for 50 to get $d=\sqrt{50^2+60^2}$ . Solve for $d$ , arriving at $\sqrt{6100}$ . Therefore, the radius of the circle is $\sqrt{6100}$ .

Finally, we have all of the components to create the equation of the circle. Plug-in 230 for $h$ , 220 for $k$ , and $\sqrt{6100}$ for $r$ .

The equation of the circle will be $(x-230)^2+(y-220)^2=6100$ .

Hope this helps :)

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2 years ago