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Luden [163]
3 years ago
15

College alcohol and drug use: In a Washington Post/Kaiser Family Foundation poll conducted from January through March 2015, 56%

of adults (ages 17-26) who attended college during the past 4 years say that alcohol and drug use at their school is a big problem. The 95% confidence 2 interval is (0.53, 0.59).
Which of the following is an appropriate interpretation of the 95% confidence interval?

a.Of random samples of the same size, 95% will have between 53% and 59% of respondents who say that alcohol and drug use at their school is a big problem.

b.There is a 95% probability that the proportion of adults (ages 17-26) who attended college during the past 4 years say that alcohol and drug use at their school is a big problem is between 53% and 59%. use at their school is a big problem is between 53% and 59%. during the past 4 years and say that alcohol and drug use at their school is a big problem

c. We are 95% confident that the proportion of the sample who say that alcohol and drug

d. We are 95% confident that the proportion of adults (ages 17-26) who attended college is between 53% and 59%.
Mathematics
1 answer:
jolli1 [7]3 years ago
7 0

Answer:

d. We are 95% confident that the proportion of adults (ages 17-26) who attended college is between 53% and 59%.

Step-by-step explanation:

Confidence interval of a proportion p.

We build a confidence interval at the x% level from a sample.

With this, we can say that we are x% sure that the true population propotion is in the interval.

The 95% confidence interval is (0.53, 0.59).

This means that we are 95% sure that the true population proportion is between 0.53 and 0.59.

So the correct answer is:

d. We are 95% confident that the proportion of adults (ages 17-26) who attended college is between 53% and 59%.

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Question:
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What we know:
- number of meeting rooms = m
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Since we need an equation to represent the number of chairs in m meeting rooms, we would multiply the amount of chairs per meeting room (325) by m. This amount is c. So the equation becomes:

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