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Luden [163]
2 years ago
15

College alcohol and drug use: In a Washington Post/Kaiser Family Foundation poll conducted from January through March 2015, 56%

of adults (ages 17-26) who attended college during the past 4 years say that alcohol and drug use at their school is a big problem. The 95% confidence 2 interval is (0.53, 0.59).
Which of the following is an appropriate interpretation of the 95% confidence interval?

a.Of random samples of the same size, 95% will have between 53% and 59% of respondents who say that alcohol and drug use at their school is a big problem.

b.There is a 95% probability that the proportion of adults (ages 17-26) who attended college during the past 4 years say that alcohol and drug use at their school is a big problem is between 53% and 59%. use at their school is a big problem is between 53% and 59%. during the past 4 years and say that alcohol and drug use at their school is a big problem

c. We are 95% confident that the proportion of the sample who say that alcohol and drug

d. We are 95% confident that the proportion of adults (ages 17-26) who attended college is between 53% and 59%.
Mathematics
1 answer:
jolli1 [7]2 years ago
7 0

Answer:

d. We are 95% confident that the proportion of adults (ages 17-26) who attended college is between 53% and 59%.

Step-by-step explanation:

Confidence interval of a proportion p.

We build a confidence interval at the x% level from a sample.

With this, we can say that we are x% sure that the true population propotion is in the interval.

The 95% confidence interval is (0.53, 0.59).

This means that we are 95% sure that the true population proportion is between 0.53 and 0.59.

So the correct answer is:

d. We are 95% confident that the proportion of adults (ages 17-26) who attended college is between 53% and 59%.

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stich3 [128]
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3 years ago
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Evaluate g(n-7) if g(x) =x^2-5 / 3x
aleksandrvk [35]

Answer:

g(n-7)=\frac{n^2-14n+44}{3n-21}

Step-by-step explanation:

The given function is

g(x)=\frac{x^2-5}{3x}

To find g(n-7), we substitute x=n-7 to obtain;

g(n-7)=\frac{(n-7)^2-5}{3(n-7)}

Expand the parenthesis to obtain;

g(n-7)=\frac{n^2-14n+49-5}{3n-21}

Simplify:

g(n-7)=\frac{n^2-14n+44}{3n-21}

7 0
3 years ago
Matt is showing his work in simplifying (6.2 − 1.6) − 4.4 + 7.8. Identify any error in his work or reasoning. Step 1: (6.2 − 1.6
Black_prince [1.1K]

Answer:

The correct option is (d)-He wrote commutative instead of associative in Step 2.

Step-by-step explanation:

Commutative property: a+b=b+a

Associative property: (a+b)+c=a+(b+c)

Now consider the provided expression.

(6.2 − 1.6) − 4.4 + 7.8

Step 1

(6.2 − 1.6) − 4.4 + 7.8

Step 2 Use Associative property

6.2 + (−1.6 − 4.4) + 7.8

Step 3: Simplify

6.2 − 6 + 7.8

Step 4: Use commutative property

14 − 6

Step 5: Simplify

14 − 6 = 8

Hence, the wrong step is step 2. He wrote commutative instead of associative in Step 2.

Therefore, the correct option is (d)-He wrote commutative instead of associative in Step 2.

8 0
3 years ago
A regression equation that predicts the price of homes in thousands of dollars is t = 24.6 + 0.055x1 - 3.6x2, where x2 is a dumm
AveGali [126]

Answer:

a) On average, homes that are on busy streets are worth $3600 less than homes that are not on busy streets.

Step-by-step explanation:

For the same home (x1 is the same), x2 = 1 if it is on a busy street and x2 = 0 if it is not on a busy street. If x2 = 1, the value of 't' decreases by 3.6 when compared to the value of 't' for x2=0. Since 't' is given in thousands of dollars, when a home is on a busy street, its value decreases by 3.6 thousand dollars.

t(x1, 0)= 24.6 + 0.055x1\\t(x1, 1) = 24.6 + 0.055x1 - 3.6\\t(x1, 1) = t(x1, 0) - 3.6

Therefore, the answer is a) On average, homes that are on busy streets are worth $3600 less than homes that are not on busy streets.

8 0
3 years ago
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Your answer is 20,000,000,000.
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