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Lerok [7]
2 years ago
8

The graph models the speed of a car over a function of time during a 3-hour trip. How far did the car go over the course of the

trip?
There is a nice way to visualize this quantity in terms of the graph. If you find it, it will help you solve this problem.

The car traveled a total of ____
miles.

Mathematics
1 answer:
Talja [164]2 years ago
5 0

The total distance travelled by the car is 80 miles.

<h3>Speed</h3>

Speed is the ratio of total distance to total time. It is given by the formula:

Speed = distance / time

From the graph:

Distance = speed * time

Total distance = 20 mph * 1 hour + (30 mph * (90 - 60)/60 hour) + (50 mph * (120 - 90)/60 hour) + (40 mph * (135 - 120)/60 hour) + (20 mph * (150 - 135)/60 hour) + (10 mph * (180 - 150)/60 hour) = 80 miles

The total distance travelled by the car is 80 miles.

Find out more on Speed at: brainly.com/question/4931057

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Which three types of transformations result in congruent shapes?
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A shipment of 18 televisions sets contains 3 defective sets. A hotel purchases 8 of these televisions sets. What is the probabil
Allisa [31]

Answer:

85.29%

Step-by-step explanation:

We know 18 televisions sets contains 3 defective sets => 15 TV sets are ok

So the total number of possible ways for the hotel to buy = C^{18} _{8} = 43758

At least one of the defective sets, so we need to find the probability for 1 defective sets, 2 defective sets and 3 defective sets.

1. The number of ways  the hotel purchases 8 of these televisions sets but have 1 defective one:

P(1) = C^{15} _{7} * C^{3} _{1} = 6435*3 = 19305

2.  The number of ways  the hotel purchases 8 of these televisions sets but have 2 defective one:

P(2) = C^{15} _{6} * C^{3} _{2} = 5005*3= 15015

3.  The number of ways  the hotel purchases 8 of these televisions sets but have 3 defective one:

P(3) = C^{15} _{5} * C^{3} _{3} = 3003*1 = 3003

So the probability that the hotel receives at least one of the defective sets =

(P(1) + P(2) + P(3) ) / P = (19305 +15015 + 3003 ) / 43785*100% = 85.29%

6 0
3 years ago
1) 15 = 5(x +2 ) 2) 5n + 34 = -2(1-7n)
Eddi Din [679]
1) 15 = 5(x + 2)
15 = 5x + 10
15 - 10 = 5x + 10 - 10
5 = 5x
5/5 = 5x/5
1 = x

2) 5n + 34 = -21(1-7n)
5n + 34 = -21 + 147n
5n + 34 = -21 + 147n
5n - 147n + 34 = -21 + 147n - 147n
-142n + 34 = -21
-142n + 34 - 34 = -21 - 34
-142n = -55
-142n/-142 = -55/-142
n = 55/142
3 0
3 years ago
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