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3 years ago

The diagram shows a swinging pendulum.

Physics

2 answers:

pashok25 [27]3 years ago

8 0

Answer:

A. The mechanical energy transforms to thermal energy as the pendulum slows and eventually stops moving.

Explanation:

took the quiz on edge

suter [353]3 years ago

5 0

Answer:

<h2>A. The mechanical energy transforms to thermal energy as the pendulum slows and eventually stops moving.</h2>

Explanation:

The law of conservation of energy states that the amount of energy is a constant, that is, it cannot be created or destroyed, it just can be transformed into different forms.

For example, in real life, a pendulum will stop moving eventually. But, why is the pendulum going to stop? Because, there's friction in that motion, which means that the energy that's being used, it's transforming into heat by friction. In terms of energy, that heat represents a subtractor of the movement.

So, the mechanical energy, which is kinetic and potenial, it's transforming to "thermal energy", making the pendulum to slow down, until stops.

Now, in a perfect environment (which doesn't exist), the pendulum would never stop, and there weren'n any heat, because there wouldn't be friction. But that's not the case here.

Therefore, the best answer is A.

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3 years ago

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Answer:

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2 years ago

An object that weighs 2.450 N is attached to an ideal massless spring and undergoes simple harmonic oscillations with a period o

Viktor [21]

Answer:

Spring constant, k = 24.1 N/m

Explanation:

Given that,

Weight of the object, W = 2.45 N

Time period of oscillation of simple harmonic motion, T = 0.64 s

To find,

Spring constant of the spring.

Solution,

In case of simple harmonic motion, the time period of oscillation is given by :

$T=2\pi\sqrt{\dfrac{m}{k}}$

m is the mass of object

$m=\dfrac{W}{g}$

$m=\dfrac{2.45}{9.8}$

m = 0.25 kg

$k=\dfrac{4\pi^2m}{T^2}$

$k=\dfrac{4\pi^2\times 0.25}{(0.64)^2}$

k = 24.09 N/m

k = 24.11 N/m

So, the spring constant of the spring is 24.1 N/m.

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3 years ago

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Answer:

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