The work that need to do is 66.24 J.
<h3>Explanation :</h3>
Hello guys, before we can count how much the work that needed to pull the toy, we should know how formula to count it first. Because the movement is with the angle, so the formula is :

If :
- W = work (J)
- F = force (N)
- s = shift (m)
- θ = elevation angle (°)
We know that :
- x = the horizontal shift = 9,2 m
- θ = elevation angle = 15°
W = work = ... J

So, the work that need to do is 66.24 J.
<u>Subject</u><u> </u><u>:</u><u> </u><u> </u><u>Physics</u><u> </u>
<u>Class</u><u> </u><u>:</u><u> </u><u>Junior</u><u> </u><u>High</u><u> </u><u>School</u><u>/</u><u>Senior</u><u> </u><u>High</u><u> </u><u>School</u><u> </u>
<u>Keyword</u><u> </u><u>:</u><u> </u><u>Work</u><u>;</u><u> </u><u>Force</u><u>;</u><u> </u><u>Shift</u><u>;</u><u> </u><u>and</u><u> </u><u>Elevation</u><u> </u><u>Angle</u><u> </u>
Answer:
=140 cm²
Explanation:
1
____ ×20x 14
2
=1
___ x base × height
is the formula have a gr8 day :)
2
Acceleration = (change in speed) / (time for the change)
change in speed = (speed at the end) - (speed at the beginning)
change in speed = (37 km/hr) - (89 km/hr) = -52 km/hr
Acceleration = (-52 km/hr) / (6 sec)
Acceleration = (-26/3) km/(hr·sec)
Units: (1/hr·sec) · (hr/3600 sec) = 1 / 3600 sec²
(-26/3) km/(hr·sec) = (-26/3) km/(3600 sec²)
= -26,000/(3 · 3600) m/s²
<em>Acceleration = -2.41 m/s²</em>
Because light is being refracted