Answer:
a) K = 1.4036 10⁻²⁰ J
, b) r = 1.23 m
Explanation:
a) The kinetic energy of the proton is
K = ½ m v²
Let's calculate
K = ½ 1.67 10⁻²⁷ (4.10 10³)²
K = 1.4036 10⁻²⁰ J
b) At the point of closest approach the hundred and potential energy are equal
U = K
q E = K
To cellular the electric field let's use Gauss's law
Ф = E dA = / ε₀
We define a Gaussian surface as a cylinder with a base perpendicular to the charge line, whereby the radius of the cylinder and the intensity of the electric field are parallel, whereby the scalar product is reduced to the algebraic product
E A = q_{int} / ε₀
The cylinder area is
A = 2π r l
We use the concept of linear density for the load inside
λ = q_{int} / l
q_{int} = λ l
We substitute
E 2π r l = λ l /ε₀
E = λ / 2π ε₀r
At the point of closest approach
q E = k
q λ / 2πε₀ r = K
r = q λ / 2πε₀ K
Calculous
r = 1.60 10⁻¹⁹ 6.00 10⁻¹² / (2π 8.85 10⁻¹² 1.4036 10⁻²⁰)
r = 1.23 m
Displacement of a body is always in a straight line in the direction of the final position regardless of the path taken to reach the final position.
Therefore, the displacement of the car can be obtained by joining the car's initial position to the final position and then counting the number of squares covered by the line. Then we multiply the number of squares by the scale and note the direction of the final position from the initial.
that is: 4×1km= 4km North since displacement is a vector.
Acceleration occurs whenever the forces on an object are unbalanced.
It's the group of forces on the object that's either balanced or unbalanced.
There's no such thing as "an unbalanced force".
it is the first one y'all