Question

1)

Answer 1

Answer:

This may take awhile, but I'm willing to do it for you!

Step-by-step explanation:

1. C
2. B
3. D
4. B (2, 1/2)
5. C
6. It was too badly formatted I couldn't depict what it was asking. Sorry.
7. A
8. B
9. Can't see the graphs. Sorry.
10. B
11. Can't see graphs. Sorry.
12. B
13. D
14. Can't see graphs. Sorry.

Very glad I was able to help!!

Answer 2

Answer:

1) C $s=\left \{ (-2,-9) \right \}$ 2) (-2,0) 3)$S=\left \{ (14,10) \right \}$ 4) $S=\left \{ \left ( 2,\frac{1}{2} \right ) \right \}$ 5) c )S={(0,3)} 6) (0,2) 7) $A) S=\left \{ \left ( 1,4 \right ) \right \}$ 8) Missing graph 9) Vertical line (check below) 10) B 11)

Step-by-step explanation:

1) Solving by the Addition/Elimination Method. Firstly, let's reduce one variable by making some algebraic adjustments and then adding it up:

$\left\{\begin{matrix}-2x&+y&=5 *(3)\\ 3x&-2y&=12 *(2)\end{matrix}\right.\Rightarrow \left\{\begin{matrix}-6x&+3y&=15 \\6x&-4y&=24 \end{matrix}\right.\Rightarrow -y=9\Rightarrow y=-9\Rightarrow 6x-4(-9)=24\Rightarrow 6x+36=24\Rightarrow 6x=-36+24\Rightarrow 6x=-12\Rightarrow x=-2\Rightarrow s=\left \{ -2,-9 \right \}$

2) Solving by Substitution Method. Where y=x+2 is plugged in the 2nd equation.

$\left\{\begin{matrix}y =&x+2 & \\ 2x-y &=-4 & \end{matrix}\right.\Rightarrow 2x-(x+2)=-4\Rightarrow 2x-x-2=-4\Rightarrow x=-4+2\Rightarrow x=-2\: and\: y=-2+2\Rightarrow y=0\Rightarrow S=\left \{ \left ( -2,0 \right ) \right \}$

3) Solving it, again, by the Substitution Method due to the I equation form:

$\left\{\begin{matrix}x=y+4& \\ 2x-3y=-2& \end{matrix}\right.\Rightarrow 2(y+4)-3y=-2\Rightarrow 2y+8-3y=-2\Rightarrow y=10\: \: x=10+4\Rightarrow x=14\Rightarrow S=\left \{ (14,10) \right \}$

4) By the Addition Method

$\left\{\begin{matrix}x+2y &=3 \\ 3x-2y &=5 \end{matrix}\right.\Rightarrow 4x=8\Rightarrow x=2\Rightarrow 2+2y=3\Rightarrow 2y=1\Rightarrow y=\frac{1}{2}\: S=\left \{ \left ( 2,\frac{1}{2} \right ) \right \}$

5) To use the graph method to solve the system of Linear equations is possible by graphing each equation on the Cartesian Plane.

Check the graph below, this system has only one solution.

c)S={(0,3)}

6) Solving y=-1/3x+2 y=x+2

(Check the graph below)

A) A) (0, 2)

7) Solving by Substitution Method:

$\left\{\begin{matrix}x=y-3 & \\ x+3y=13& \end{matrix}\right.\Rightarrow y-3+3y=13\Rightarrow 4y=13+3\Rightarrow 4y=16\Rightarrow y=4\: \: \\x=4-3\Rightarrow x=1 \\S=\left \{ \left ( 1,4 \right ) \right \}$

8) Missing graph

9)

$\frac{1}{2}x+x=1+2\Rightarrow \frac{3}{2}x=3\Rightarrow x=2\\ S=\{2}$

Check the graph below its answer

10) Solving by the Addition Method

$\left\{\begin{matrix}x+3y=5 & \\ -x+6y=4& \end{matrix}\right.\Rightarrow 9y=9\Rightarrow y=1 \: \: And \: \: x+3(1)=5\Rightarrow x=5-3\Rightarrow x=2\\S=\left \{ \left ( 2,1 \right ) \right \}$

11) Sorry, missing graph for the question.

12) Sorry, missing graph for the question.

13) D Check the graph below

14) Sorry, missing graph for the question.