4 years ago

Find the product. (3b – 6ys^2) (b - ys^2)

Mathematics

1 answer:

kifflom [539]4 years ago

8 0

Answer:

idk

Step-by-step explanation:

idk

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Please help! 3 Questions please show how you solved the problem

Masteriza [31]

Answer:

1) $(-y^2-4y-8+4y^2+6y-3)$

2) $32x^5y^4z^2$

3) $x^3-9x^2+14x+24$

Step-by-step explanation:

Given the expression we have to simplify the expression

1) $(-y^2-4y-8)-(-4y^2-6y+3)$

⇒ $(-y^2-4y-8+4y^2+6y-3)$

Combining like terms, we get

⇒ $3y^2+2y-11$

2.) $(2x^2y^3z^2)(4xy.4x^2)$

⇒ $(2x^2y^3z^2)(16x^3y)$

⇒ $32x^5y^4z^2$

3.) $(x-4)(x^2-5x-6)$

⇒ $x^3-5x^2-6x-4x^2+20x+24$

⇒ $x^3-9x^2+14x+24$

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sukhopar [10]

Let’s use y as a replacement for a number. You would do 3y-7 since you multiply by three and take away seven.

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3y-5=5y<br><br> What is the value of y?

navik [9.2K]

The value of Y would be -5 = 2y

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butalik [34]

C. (5, -11) hope this helps and I’m like sure sure it’s right

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Which expression is equivalent to 6/6

trapecia [35]

Answer:

1/1 I think I hope this helps

Step-by-step explanation:

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