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3 years ago

Find the product. (3b – 6ys^2) (b - ys^2)

Mathematics

1 answer:

kifflom [539]3 years ago

8 0

Answer:

idk

Step-by-step explanation:

idk

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I need to find the area of the shaded region, can anyone explain how to do it?

vesna_86 [32]

Answer:

Step-by-step explanation:

JM is a diameter. 1/2 JM is the radius. 1/2 10 = 5

The radius is 5

The above statement is true if N is the center.

The semi circle has an area of pi r^2/2 = 5^2/2 * pi = 25/2 * pi

12.5 pi

The area of the other part is

(58/360) * pi * r^2 =

0.161 * pi * 5^2

0.161 * pi * 25

4.03 * pi

Now add these two parts together.

12.5pi + 4.03= 16.53 * pi.

That's one possible answer.

Another would be 16.53 * 3.14 = 51.897

If you have choices, list them.

5 0

3 years ago

Choose the expression that could be used to solve this problem.davin spent $8.40 for gasoline. he saw gas priced at $1.40/gal an

alex41 [277]

$1.40 • y = $8.40 I hope that helps

6 0

3 years ago

Prove each statement that is true and ﬁnd a counterexample for each statement that is false. Assume all sets are subsets of a un

tekilochka [14]

Answer with Step-by-step explanation:

We are given that A, B and C are subsets of universal set U.

We have to prove that

$A\cap (B-C)=(A\cap B)-(A\cap C)$

Proof:

Let x $\in A\cap (B-C)$

Then $x\in A$ and $x\in(B-C)$

When $x\in ( B-C)$ then $x\in B$ but $x\notin C$

Therefore, $x\in( A\cap B)$ but $x\notin (A\cap C)$

Hence, it is true.

Conversely , Let $x\in(A\cap B)$ but $x\notin(A\cap C)$

Then $x\in A$ and $x\in B$

When $x\notin ( A\cap C)$ then $x\notin C$

Therefor, $x\in A\cap (B-C)$

Hence, the statement is true.

5 0

2 years ago

I NEED HELP ASAPPPPP

soldier1979 [14.2K]

Answer:

y=55 degrees x=125 degrees

Step-by-step explanation:

6 0

2 years ago

4 1/6 + 5 2/3<br><br> Enter your answer as a mixed number in simplest form

anyanavicka [17]

Answer:9 5/6

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers