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Zolol [24]
3 years ago
7

Determine whether 81 − 49n4 is a difference of two squares. If so, factor it. If not, explain why.

Mathematics
1 answer:
Mumz [18]3 years ago
7 0

We have

81-49n^4=9^2-(7n^2)^2

so this is indeed a difference of squares. Factorizing would give

81-49n^4=(9-7n^2)(9+7n^2)

making the answer D.

We can further factor the first term here and write

9-7n^2=3^2-(\sqrt 7\,n)^2=(3-\sqrt7\,n)(3+\sqrt7\,n)

but that's clearly out of the scope of this question.

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