Answer:
Did you cop the strawberry coughs?
Step-by-step explanation:
Answer:
Step-by-step explanation:
length=1 m
base of triangle=10 m
height=5m
volume= 1/2×10×5×1=25 m cube.
slant height l=√(5²+5²)=√50=5√2
slant surface area=2[5√2×1]=10√2
area of front and back=2×1/2(10×5)=50
total surface area=50+10√2≈50+14.14≈64.14 m²
Answer:
It is the 3rd choice. It is 4 times as big as the smaller cylinder
Step-by-step explanation:
V = πr2h
r - radius
h - height
π - pi
= π(3)2(10)
enter into a calucaltor and you get 282.74
= π(6)2(10)
enter into a calucaltor and you get 1130.97
Divide 1130 by 282 and you get about 4
Answer:
I'm not going to give you the answer because you need to learn this on your own because it isn't hard.
Step-by-step explanation:
There are 4 main things you investigate in a number line: the median, the mode, the range, and mean. The median is the middle of your data set. You find the number of all of your data and find out the middle of that number. You find what line it is in on your data set. The range is the variety of numbers in your data set (for yours its 10). The mean is the average of your data set. The mode is the number that pops up the most (in your case, 2).
Answer:
The lower class boundary for the first class is 140.
Step-by-step explanation:
The variable of interest is the length of the fish from the North Atlantic. This variable is quantitative continuous.
These variables can assume an infinite number of values within its range of definition, so the data are classified in classes.
These classes are mutually exclusive, independent, exhaustive, the width of the classes should be the same.
The number of classes used is determined by the researcher, but it should not be too small or too large, and within the range of the variable. When you decide on the number of classes, you can determine their width by dividing the sample size by the number of classes. The next step after getting the class width is to determine the class intervals, starting with the least observation you add the calculated width to get each class-bound.
The interval opens with the lower class boundary and closes with the upper-class boundary.
In this example, the lower class boundary for the first class is 140.
