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3 years ago

9

Pythagorean’s 14 in 15 in x

1 answer:

Flura [38]3 years ago

5 0

Answer:

210x

Step-by-step explanation:

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The solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Solution:

Given equation:

$-2 x^{2}+y=-5$

Add $2 x^{2}$ on both sides.

$-2 x^{2}+y+2 x^{2}=-5+2 x^{2}$

$y=-5+2 x^{2}$ -------- (1)

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Equate (1) and (2).

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$-5+2 x^{2}+3 x^{2}=-3 x^{2}+5 +3 x^{2}$

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Taking square root on both sides, we get

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