Answer:
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
5. y = x + 7
6. y = -x + 1
Step-by-step explanation:
By Pythagoras' theorem,
12^2 = 11^2 + height^2
height = ±√12^2 - 11^2 (rej -ve value since height > 0)
height = 16.279 (5sf) = 16.3 (nearest tenth place)
Topic: Pythagoras theorem
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96$ source: just trust me bro
9/20 is the probability that Bob's password consists of an odd single-digit number followed by a letter and a positive single-digit number
It is given that bob's password consists of a non-negative single-digit number followed by a letter and another non-negative single-digit number (which could be the same as the first one).
P (odd single digit number ) = ( 5 odd single digits / 10 non-negative single digits) = (5/10) = 1/2
P (positive single digit number ) = (9 positive single digits / 10 non-negative single digits) = 9/10
The total probability is (1/2) (9/10) = 9/20
Learn more about word problems here: brainly.com/question/21405634
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