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2 years ago

A store sells 8 cans of nuts for $18. how much would it cost to buy 3 cans of nuts

2 answers:

7 0

$\bf \begin{array}{ccll}\stackrel{nuts}{cans}&\$\\\cline{1-2}8&18\\3&x\end{array}\implies \cfrac{8}{3}=\cfrac{18}{x}\implies x=\cfrac{3\cdot 18}{8}\implies x=\cfrac{27}{4}\implies x=6\frac{3}{4}$

steposvetlana [31]2 years ago

4 0

Answer:

$6.75

Step-by-step explanation:

We can put the first sentence into an equation. c is equal to the cans of nuts.

8c = 18

We can solve this equation by dividing both sides by 8 to get

c = 18 ÷ 8

18 divided by 8 is 2.25

This means that each can is worth $2.25

To get the price of 3 cans, we can multiply 3 by 2.25

The answer is

$6.75

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A theatre group sold a total of 440 tickets for a show, making a total of $3940. Each regular ticket cost $5, each premium ticke

valentina_108 [34]

Answer: 330 regular tickets, 46 premium tickets and 64 elite tickets were sold.

Step-by-step explanation:

Let x represent the number of regular tickets that were sold.

Let y represent the number of premium tickets that were sold.

Let z represent the number of elite tickets that were sold.

The theatre group sold a total of 440 tickets for the show. It means that

x + y + z = 440- - - - - - - - - -1

Each regular ticket cost $5, each premium ticket cost $15, and each elite ticket cost $25. The total amount made from the show was $3940. It means that

5x + 15y + 25z = 3940- - - - - - - - - 2

The number of regular tickets was three times the number of premium and elite tickets combined. It means that

x = 3(y + z)

x = 3y + 3z

Substituting x = 3y + 3z into equation 1 and equation 2, it becomes

3y + 3z + y + z = 440

4y + 4z = 440- - - - - - - - - - - - -3

5(3y + 3z) + 15y + 25z = 3940

15y + 15z + 15y + 25z = 3940

30y + 40z = 3940 - - - - - - - - - - 4

Multiplying equation 3 by 10 and equation 4 by 1, it becomes

40y + 40z = 4400

30y + 40z = 3940

Subtracting, it becomes

10y = 460

y = 460/10

y = 46

Substituting y = 46 into equation 3, it becomes

4 × 46 + 4z = 440

184 + 4z = 440

4z = 440 - 184

4z = 256

z = 256/4

z = 64

x = 3(y + z) = 3(46 + 64)

x = 330

4 0

3 years ago

(Before you answer I am looking for how I do it. I have the answers but I need to know an equation to do this instead of using l

Tema [17]

Answer:

14 and 16.

Step-by-step explanation:

We know that two consecutive even numbers is 30.

Let's let n be any number.

Then the first even number must be 2n.

This is because n can be any number, either even or odd. However, if we multiply it by 2, this ensures that 2n is even. Remember that any number multiplied by 2 yields an even number.

Therefore, the consecutive even number will be (2n+2). Not (2n+1), because that gives an odd number.

We know that they sum to 30. So, we can write the following equation.

$(2n)+(2n+2)=30$

And we solve from there:

$4n+2=30\\\Rightarrow4n=28\\\Rightarrow n=7$

So, the value of n is 7.

Therefore, the first even number is 7(2)=14.

And the consecutive even number is 16.

Edit: Typo

7 0

2 years ago

How to find the base of an isosceles when given one side

MA_775_DIABLO [31]

Double the side and subtract by 360

3 0

2 years ago

Solve 2(b − 3) ≥ 3(3 − b) and describe the graph of the solution. Show all your work.

solong [7]

Answer:

$\large\boxed{b\geq3\to b\in[3,\ \infty)}$

Step-by-step explanation:

$2(b-3)\geq3(3-b)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\(2)(b)+(2)(-3)\geq(3)(3)+(3)(-b)\\\\2b-6\geq9-3b\qquad\text{add 6 to both sides}\\\\2b-6+6\geq9+6-3b\\\\2b\geq15-3b\qquad\text{add}\ 3b\ \text{to both sides}\\\\2b+3b\geq15-3b+3b\\\\5b\geq15\qquad\text{divide both sides by 5}\\\\\dfrac{5b}{5}\geq\dfrac{15}{5}\\\\b\geq3$