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Misha Larkins [42]
3 years ago
11

students in mr.halperts class are measuring the width of a rectangle that is 6 2/3 inches. the length of the rectangle is twice

its width. what is the perimeter of the rectangle?
Mathematics
1 answer:
Korolek [52]3 years ago
3 0

Answer:

Finding Length and Width When You Know Area and Perimeter

If you happen to know the distance around the rectangle, which is its perimeter, you can solve a pair of equations for L and W. The first equation is that for area, A = L ⋅ W, and the second is that for perimeter, P = 2L + 2W

Step-by-step explanation:

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Use integration by parts to derive the following formula from the table of integrals.
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Answer:

I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)

Step-by-step explanation:

for

I= ∫x^n . e^ax dx

then using integration by parts we can define u and dv such that

I= ∫(x^n) . (e^ax dx) = ∫u . dv

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u= x^n → du = n*x^(n-1) dx

dv= e^ax  dx→ v = ∫e^ax dx = (e^ax) /a ( for a≠0 .when a=0 , v=∫1 dx= x)

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