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Misha Larkins [42]
3 years ago
11

students in mr.halperts class are measuring the width of a rectangle that is 6 2/3 inches. the length of the rectangle is twice

its width. what is the perimeter of the rectangle?
Mathematics
1 answer:
Korolek [52]3 years ago
3 0

Answer:

Finding Length and Width When You Know Area and Perimeter

If you happen to know the distance around the rectangle, which is its perimeter, you can solve a pair of equations for L and W. The first equation is that for area, A = L ⋅ W, and the second is that for perimeter, P = 2L + 2W

Step-by-step explanation:

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nexus9112 [7]
The height is around 4.77 mm
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3 years ago
1.) Determine whether each number is irrational or rational.
nalin [4]

Answer:

1/3 is rational its nonterminating but it repeats

6.99999 rational its nonterminating and it repeats also

7.48331 is irrational because its non terminnating  and it does not repeat

Step-by-step explanation:

8 0
3 years ago
Given a focus of (4, 5) and directrix of y= -3 , find the equation of the parabola.
andrey2020 [161]
Check the picture below.

notice, the focus point is at 4,5 whilst the directrix line is at y = -3, below the focus point, meaning the parabola is vertical and opening upwards.

keeping in mind that the vertex is "p" distance from either of these fellows, then the vertex is half-way between both of them, notice in the picture, the distance from y = 5 to y = -3 is 8 units, half that is 4 units, thus the vertex 4 units from the focus or 4 units from the directrix, that puts it at (4,1), whilst "p" is 4, since the parabola is opening upwards, is a positive 4 then.

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
(y-{{ k}})^2=4{{ p}}(x-{{ h}})
\\\\
\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}})}
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-------------------------------

\bf \begin{cases}
h=4\\
k=1\\
p=4
\end{cases}\implies (x-4)^2=4(4)(y-1)\implies (x-4)^2=16(y-1)
\\\\\\
\cfrac{1}{16}(x-4)^2=y-1\implies \cfrac{1}{16}(x-4)^2+1=y

8 0
3 years ago
2.) A cubic function that has 3 zeros: 2, -5, and 7.
stiv31 [10]

Answer:

65

Step-by-step explanation:

8 0
3 years ago
What is the product mentally of (ab + 3)(ab - 3)
AleksAgata [21]

Answer:

ab² - 9

Step-by-step explanation:

Given in the question an expression

(ab + 3)(ab - 3)

To product mentally we will use polynomial identity called

Difference of squares

<h3>a² - b² = (a+b)(a-b) </h3>

here a = ab

        b = 3

(ab + 3)(ab - 3) = ab² - 3² = ab² - 9

3 0
3 years ago
Read 2 more answers
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