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3 years ago

PLEASE HELP ME ASAP!

Mathematics

2 answers:

romanna [79]3 years ago

6 0

Answer:

x =- 3 and y = -7

Step-by-step explanation:

2X-2Y=-8

X=2y + 11

We need to isolate both X and Y in both equations

2x-2y=-8

(add 2y to both sides)

2x=-8+ 2y

(divide both sides by 2)

x=-4+y and x=2y+11

because both of these equations are the same we can put them together

4+y=2y+11

(subtract y)

4=y+11

(subtract 11)

-7=y

so y = -7

then to find x you just need to plug in y to one of the equations

x=2(-7) + 11

x= -14 +11

x = -3

Klio2033 [76]3 years ago

3 0

Answer:

x = - 19, y = - 15

Step-by-step explanation:

Given the 2 equations

2x - 2y = - 8 → (1)

x = 2y + 11 → (2)

Substitute x = 2y + 11 into (1)

2(2y + 11) - 2y = - 8 ← distribute and simplify left side

4y + 22 - 2y = - 8

2y + 22 = - 8 ( subtract 22 from both sides )

2y = - 30 ( divide both sides by 2 )

y = - 15

Substitute y = - 15 into (2) for corresponding value of x

x = 2(- 15) + 11 = - 30 + 11 = - 19

Solution is x = - 19, y = - 15

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3 years ago

Solve for x & y solve x = 3 + yy = -2x + 9

sergey [27]

x = 3 + y Eqn(1)

y = -2x + 9 Eqn(2)

Let us solve the system of equations with the substitution method

x - 3 = y (Subtracting 3 from both sides of the Eqn(1))

Replacing y = x - 3 in Eqn (2), we have:

x - 3 = -2x + 9

x = -2x + 9 + 3 (Adding 3 to both sides of the equation)

x + 2x = 9 + 3 (Adding 2x to both sides of the equation)

3x = 12 ( Adding like terms)

x = 12/3 (Dividing by 3 on both sides of the equation)

x = 4

Replacing x=4 in Eqn(1), we have:

4 = 3 + y

4 - 3 = y (Subtracting 3 from both sides of the equation)

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6 0

1 year ago

Determine the value of x. A. 4√2 B. 2/√2 C. 2√2 D. 2

ZanzabumX [31]

Answer:

$\huge\boxed{\sf C.}$

Step-by-step explanation:

sin 45 = opposite / hypotenuse

Where opposite = x , hypotenuse = 4

sin 45 = x / 4

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3 0

3 years ago

Given the function g(x) = x^3 − (8+1)x^2-4(9+2)x+(5x2-1) determine where the function is quickly(slowly) increasing (decreasing)

Elenna [48]

Answer:

hence g(x) is increasing at point x= 3+14i,3-14i

Step-by-step explanation:

given, g(x)=x^3-(8+1)x^2-4(9+2)x+5x2-1

g(x)=x^3-9x^2-44x+10x-1

g(x)=x^3-9x^2-34x-1

$\frac{\partial g(x)}{\partial x}$ =3x^2-18x-34

for increasing and decreasing function,

3x^2-18x-34=0

x=3+14i $\geq$ 0

x=3-14i $\geq$ 0

hence g(x) is increasing at point x= 3+14i,3-14i answer

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3 years ago