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almond37 [142]
3 years ago
6

What is the probability of flipping a coin 85 times and getting tails 40 times or fewer? Round your answer to the nearest tenth

of a percent.
A. 99.8%
B. 95.9%
C. 33.2%
D. 0.4%
Mathematics
1 answer:
Ilya [14]3 years ago
5 0

Answer:

C. 33.2%

Step-by-step explanation:

Number of trials n = 85

Probability of success p = 0.5

Number of successes r = 40

Use cumulative binomial probability:

P(x ≤ r) = binomcdf(n, p, r)

P(X ≤ 40) = binomcdf(85, 0,5, 40)

P(x ≤ 40) = 0.332

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Answer:

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Step-by-step explanation:

Two Tangent Theorem: Tangents which meet at same point are equal in length.

Here tangents at J and H meet at I.

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Step-by-step explanation:

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Arthur is interested in the effects of sleep deprivation usage on number of calories consumed. He asks a group of 20 college stu
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Arthur knows that there is a difference among the groups somewhere, but he does not know where

Step-by-step explanation:

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In the context, Arthur is doing a study and he wishes to find out effect of a sleep deprivation on the number of the calories that people consumed. He collects some data from his subject group from the sleep lab and after running the ANOVA test, he finds out that he can reject the null hypothesis. So on this basis, Arthur knows that there is some basic difference among the members of the group somewhere, but he does not know where actually the difference is.

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Answer:

138 students

Step-by-step explanation:

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The rate of growth of profit​ (in millions) from an invention is approximated by Upper P prime (x )equals x e Superscript negati
Alecsey [184]

Answer:

The function is  P(x) =  \frac{1}{2} e^{-x^2} +0.016

Step-by-step explanation:

From the question we are told that

    The rate of growth  is  P'(x) =  xe^{x} - x^2

     The total profit is P(2)  =$25,000

      The time taken to make the profit is x =  2 \ years

         

From the question

     P'(x) =  xe^{-x^2}  is the rate of growth

  Now here x represent the time taken

Now the total profit is mathematically represented as

       P(x) =  \int\limits {P'(x)} \,  =   \int\limits {xe^{-x^2}} \,

So using substitution method

   We have that

                      u =  - x^2

                      du =  2xdx

  So  

        p(x) =  \int\limits {\frac{1}{2} e^{-u}} \, du

       p(x) =  {\frac{1}{2} [ e^{-u}} +c ]

       p(x) =  {\frac{1}{2}  e^{-x^2}} + \frac{1}{2} c      recall  u =  - x^2   and  let  \frac{1}{2} c =  Z

       

At  x =  2 years  

     P(x)  =$25,000

So

       Since the profit rate is in million

    P(x)  =$25,000 = \frac{25000}{1000000} =$0.025 millon dollars

So  

       0.025 =  {\frac{1}{2}  e^{-2^2}} + Z  

=>    Z = 0.025 - {\frac{1}{2}  e^{-2^2}}  

       Z = 0.016  

So the profit function becomes

         P(x) =  \frac{1}{2} e^{-x^2} +0.016

     

       

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