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3 years ago

Please help me with homework

Mathematics

1 answer:

xenn [34]3 years ago

4 0

2-14:

A) 3x+5y=3(3)+5(2)

=9+10

=19

B) x²+y²=3²+2²

=9+4

=13

C) -5x+9=-5(3)+9

=-15+9

=-6

D) xy-1=(2×3)-1

=6-1

E) 2x²-y=2(3)²-2

=18-2

=16

F) 2y-x+5+x²-3y=2(2)-3+5+3²-3(2)

=4-3+5+9-6

2-15: area=y²+xy+xy

=(y²+2xy) un²

perimeter=y+y+y++y+x+y/2+y+x+y/2

=(6y+2x) un

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The sum of a number and six times its reciprocal is 10. Find the number

Andreas93 [3]

Answer:

two solutions work: x = 5 + $\sqrt{19}$ and x = 5 - $\sqrt{19}$

Step-by-step explanation:

x + 6 ( 1/x ) = 10

x^2 + 6 = 10x

x^2 - 10x + 6 = 0

x = 5 + $\sqrt{19}$ , 5 - $\sqrt{19}$

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3 years ago

Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.

mart [117]

Answer:

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

Step-by-step explanation:

The given expression is

$\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}$

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

$\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}$ $[\because a^ma^n=a^{m+n}]$

$\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}$

$\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is $\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

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4 years ago

Evaluate the expression when y=-3.<br> y2 + 6y +8

jenyasd209 [6]

-6-18+8=-16
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3 years ago

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How do you find the missing angle of a triangle when all other angles are there?

olya-2409 [2.1K]

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3 years ago

Matt and Mark went to El Rodeo to have some dinner. Matt ordered 3 tacos and 2 enchiladas, which cost him $4.93. Mark ordered 2

lord [1]

Answer:

The cost of one taco is $0.87 and the cost of one enchilada is $1.16

Step-by-step explanation:

Let the cost of tacos be X

and cost of enchiladas be y

So, by using given data, we have following equations

3X + 2Y = 4.93 (1)

2X + 4Y = 6.38 (2)

So, first multiply 1st equation by 2 and 2nd equation by 3, then subtracting 1st equation by 2nd.

= 2 × ( 3X + 2Y = 4.93) (1)

= 3 × (2X + 4Y = 6.38) (2)

= - (6X + 4Y = 9.86) (1)

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= 8Y = 9.28

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By putting the value of Y in equation 1, we get

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Hence, the cost of one taco is $0.87 and the cost of one enchilada is $1.16.

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3 years ago