Im being timed so please help-

Which of the following is the product of the rational expressions shown below? 7x/x-4•x/x+7

LiRa [457]

<h2>The product of the rational expressions $\dfrac{7x}{x-4}.\dfrac{x}{x+7}$ = $\dfrac{7x^2}{x^2+3x-28}$ </h2>

Step-by-step explanation:

We have,

$\dfrac{7x}{x-4}.\dfrac{x}{x+7}$

To find, the product of the rational expressions $\dfrac{7x}{x-4}.\dfrac{x}{x+7}$ = ?

∴ $\dfrac{7x}{x-4}.\dfrac{x}{x+7}$

= $\dfrac{7x.x}{(x-4)(x+7)}$

= $\dfrac{7x^2}{(x(x+7)-4(x+7)}$

= $\dfrac{7x^2}{x^2+7x-4x-28}$

= $\dfrac{7x^2}{x^2+3x-28}$

Thus, the product of the rational expressions $\dfrac{7x}{x-4}.\dfrac{x}{x+7}$ = $\dfrac{7x^2}{x^2+3x-28}$

5 0

3 years ago

I need shown work with numbers or an explanation if need.

sveticcg [70]

Let us denote the semi arcs as congruent angles. This means that angles FEJ and EFJ are congruent (That is, they have the same measure). Since angles FEJ and EFJ have the same measure, this implies that sides EJ and FJ are equal. Since angles EJK and FJH are supplementary angles to angle EJF, this implies that EJK and FJH have the same measure.

Using the Angle Side Angle (SAS) criteria, we determine that triangles EKJ and triangle FJH are congruent. This implies that sides EK and FH are equal and that angles EKJ and FHJ are congruent. Note that angle EKJ is the same as EKF and that FHJ is the same as FHE.

Once again, since angles EKF and FHJ are congruent, and angle EKD is supplementary to the angle EKJ when angle FHG is supplementary to angle FHJ, then we have that angles EKD and angle FHG are congruent.

Using again the SAS criteria, we determine that triangles EKD and FHG are congruent.

From this reasoning, we have proved the following facts:

Triangle DEK is congruent to triangl GFH

Angle EKF is congruent to angle FHE

Segment EK is the same as segment FH

4 0

1 year ago

PLEASE HELP FAST!

svetlana [45]

Answer:

B

Step-by-step explanation:

y × y = $y^{2}$

y × -3 = -3y

$y^{2} -3y$

4 0

3 years ago

Read 2 more answers

Please name all of the property of multiplication for 4*(-3)*5

PIT_PIT [208]

Answer:

Step-by-step explanation:

You can multiply -3 by 4 and then multiply the result of that by 5, or you could write -3, 4 and 5 in other orders (6 possible orders) and obtain the same result.

I would multiply (-3) by 4, obtaining -12, and then multiply this -12 by 5, obtaining -60. But I could also multiply 5 by 4, obtaining 20, and then multiply this 20 by -3, obtaining the same -60.

What I have described here are the commutative and associative properties of multiplication.

6 0

3 years ago

An observer in tower A sees a boat 1538 yd away at an angle of depression of 35°. To the nearest yard, how far is the boat away

Thepotemich [5.8K]

From my own solution, my answer is closest to D. 1951 yd; 27°

The boat is 1951 yards away from the observer in tower B. The angle of depression to the boat from Tower B is 27°.

Pls. see my attachment.

In it I divided the big triangle into two small right triangles.
I solved for the common leg of the right triangles by using sin theta formula. sin θ = opposite / hypotenuse

sin 35° = opposite / 1538 yd
sin 35° * 1538 yd = opposite
882.16 yd = opposite

From there, I used the Pythagorean theorem to solve for the missing side which is part of the 3,000 yd measure.

I got the measure of 1,259.86 yards. The remaining measure of 1,740.14 is the side of the other right triangle.

Still using Pythagorean Theorem, I used the measurement of the known side of the 2nd right triangle to solve for its hypotenuse which was 1,950.97 or 1,951 yards.

With regards to the angle of depression, I used this formula:

tan(y) = opposite / adjacent
tan(y) = 1538 yd / 3000 yd
tan(y) = 0.513
y = 0.513/tan
y = 27.14°

8 0

3 years ago

Im being timed so please help-​

Im being timed so please help-