Write an equation for :<br><br> Three times a number decreased by five is equal to twenty five.

A production process is known to produce a particular item in such a way that 5 percent of these are defective. If two items are

IRINA_888 [86]

Answer:

0.0025 = 0.25% probability that both are defective

Step-by-step explanation:

For each item, there are only two possible outcomes. Either they are defective, or they are not. Items are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5 percent of these are defective.

This means that $p = 0.05$

If two items are randomly selected as they come off the production line, what is the probability that both are defective

This is P(X = 2) when n = 2. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.05)^{2}.(0.95)^{0} = 0.0025$

0.0025 = 0.25% probability that both are defective

4 0

2 years ago

Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t

Gnom [1K]

Answer:

Second class have higher marks and greater spread.

Step-by-step explanation:

First box plot represents class first. From the first box plot, we get

$\text{Minimum value }= 53,Q_1=62,Median=80,Q_3=86,\text{Maximum value }= 89$

$Range=Maximum-Minimum=89-53=36$

$IQR=Q_3-Q-1=86-62=24$

Second box plot represents class second. From the second box plot, we get

$\text{Minimum value }= 56,Q_1=62,Median=74,Q_3=89,\text{Maximum value }= 96$

$Range=Maximum-Minimum=96-56=40$

$IQR=Q_3-Q-1=89-62=27$

First class has greater minimum value, first quartile of both classes are same, second class has greater median, first class has greater third quartile and first class has greater maximum value. It means second class have higher marks but class first have less variation.

Second class has greater range and greater inter quartile range. It means data of second class has greater spread.

Therefore, second class have higher marks and greater spread.

3 0

3 years ago

Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Determine each segment length in right triangle .

Pani-rosa [81]

The segment length is 14 (square root)2

Given that Triangle ABC is right angle triangle

The vertex marked is B where side AC is the hypotenuse

The side of AC is at Vertex B is 14

The dash segment from vertex B to point D on side AC

Angle BDA is marked right angle .

Angles A and C both marked 45 degrees.

As shown in diagram

Triangle ABC is drawn according to the statement where B is vertex

The side lengths are 14

Now to find Another side length that is x

So , the equation formed is

x*cos45 = 14

x/√2 = 14

x = 14√2

Hence the length of the segment is 14√2

Learn more about Right angle triangle here brainly.com/question/64787

#SPJ1O

5 0

1 year ago

What is the common denominator for 1 2/3 and 3/4

Elena L [17]

Answer:

The answer is 12

Step-by-step explanation:

Multiply 1*3

Add 2 to the number

Change the first number to 5/3

Multiply 3*4

3 0

2 years ago

Nevermind i got the answer

Gwar [14]

Answer:

Good job! :)

Step-by-step explanation:

3 0

3 years ago

Write an equation for : Three times a number decreased by five is equal to twenty five.