Given:
Origin of the clock face (0,0)
label 12 point (0,5)
I am assuming that the radius of the clock is 5 units.
Label 6 should be placed on the point (0,-5). The point of label 12 should be reflected across the x-axis and labeled as 6 of the clock face.
Answer:
m=-3
Step-by-step explanation:
move the -22 to the other side by adding 22 on both sides:
m-22+22=-25+22
Simplify:
m=-3
Answer: m=-3
Hope this helps!
Answer:
1/4
Step-by-step explanation:
use 2 points from the graph (-4,5) and (0,6) and put them in the distance equation.
(y2-y1)
----------
(x2-x1)
6-5
-------
0-(-4)
1/4
Infanate solution I think???
The equation of the graphed parabola is y=a-4.
Given that parabola is plotted, concave up , with vertex located at coordinates (-3,-4).
We are required to find the equation of the graphed parabola.
The equation of a quadratic function of vertex (h,k) is given by:
y=a+k
In the above equation a is the leading coefficient.
We have been given point (-3,-4).
We have to just put the value of h=-3 and k=-4 and the required equation will be as under:
y=a-4
Hence the equation of the parabola which is plotted, concave up, with vertex located at coordinates (-3,-4) is y=a-4.
Learn more about parabola at brainly.com/question/64712
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