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4 years ago

I WILL MAKE YOU BRAINLIEST! 46 POINTS!!!!! PLEASE HURRY! BRAINLIEST, THANKS, AND 5 STARS! PROMISE!

1 answer:

6 0

A ray is a simple way to show all the solutions to an inequality. When an inequality represents a practical problem, some of the points may not make sense as solutions.

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Caroline can sketch 5 cartoon strips in ten hours. How long will it take her to sketch 2 strips?

svet-max [94.6K]

Answer: Hello, 10 hours.

Step-by-step explanation: 2 cartoon strips takes 5 hours

divide 5 by 2 to give us how much time is used for 1 strip

5/2 = 2.5 which is equal to 1 strip

Now the question is asking you how much will time for 4 strips?

Take 4 and multiply it by 2.5

4x2.5 = 10

5 0

3 years ago

Read 2 more answers

The temperature fell from 0°F to 6 3/5°F below 0°F in 2 1/5 hours. What was the temperature change per hour.

kakasveta [241]

Answer With Step-by-step explanation:

C: 3

This is because 6 3/5 is a positive number, and 6 3/5 ÷ 2 1/5 = 3

Hope this was helpful! (brainliest please)

6 0

3 years ago

How do you know if a solution is extraneous?

krek1111 [17]

Answer:to determine if a solution is extraneous, we simply plug the solution into the original equation.

Step-by-step explanation:

hope this helps!

4 0

2 years ago

Read 2 more answers

What is a quarter of 2770?

pentagon [3]

Answer:

692.5

Step-by-step explanation:

4 0

3 years ago

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The angle 0 lies in Quadrant II . <br>Cos 0 = <br><img src="https://tex.z-dn.net/?f=%20-%20%20%5Cfrac%7B2%7D%7B3%7D%20" id="TexF

mel-nik [20]

Answer:

$\tan(\theta)=\frac{-\sqrt{5}}{2}$

Step-by-step explanation:

Since we are in quadrant 2, sine is positive. Since sine is positive and cosine is negative, then tangent is negative.

Now I'm going to find the sine value of this angle given using one of the Pythagorean Identities, namely $\sin^2(\theta)+\cos^2(\theta)=1$ .

If given $\cos(\theta)=\frac{-2}{3}$ , then we have $\sin^2(\theta)+(\frac{-2}{3})^2=1$ by substitution of $\cos(\theta)=\frac{-2}{3}$ .

Let's solve:

$\sin^2(\theta)+(\frac{-2}{3})^2=1$ for $\sin(\theta)$ .

$\sin^2(\theta)+\frac{4}{9}=1$

Subtract 4/9 on both sides:

$\sin^2(\theta)=1-\frac{4}{9}$

Simplify:

$\sin^2(\theta)=\frac{5}{9}$

Square root both sides:

$\sin(\theta)=\sqrt{\frac{5}{9}}$

$\sin(\theta)=\frac{\sqrt{5}}{\sqrt{9}}$

$\sin(\theta)=\frac{\sqrt{5}}{3}$

===========

$\tan(\theta)=\frac{\sin(\theta)}{\cos(\theta)}=\frac{\frac{\sqrt{5}}{3}}{\frac{-2}{3}}$

Multiplying top and bottom by 3 gives:

$\tan(\theta)=\frac{\sqrt{5}}{-2}$

I'm going to move the factor of -1 to the top:

$\tan(\theta)=\frac{-\sqrt{5}}{2}$

7 0

3 years ago