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Natali [406]
3 years ago
11

5√-54 in simplest radical form

Mathematics
1 answer:
rjkz [21]3 years ago
7 0

YOUR ANSWER IS 15i radical 6


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Find the value of x in each figure
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Because angle VZW and angle WZX are supplementary, you need to place (3x +17)+ (x-9)=180
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4 years ago
What is the initial value in the equation f(x) = 350(1 - 0.12)^x? *
kvasek [131]

Given:

The function is:

f(x)=350(1-0.12)^x

To find:

The initial value of the function.

Solution:

We have,

f(x)=350(1-0.12)^x

The value of the function at x=0 is called the initial value of the function.

For x=0, we get

f(0)=350(1-0.12)^0

f(0)=350(0.88)^0

Clearly 0.88 is a non zero number and zero to the power of a non zero number is always 1.

f(0)=350(1)

f(0)=350

Therefore, the initial value of the function is 350.

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3 years ago
The hawks lost eighty three games they won 14 more than they lost. how many games did they win?
Daniel [21]
The hawks won 97 games 
5 0
3 years ago
Read 2 more answers
Randall wants to buy a pizza. He can select from 5 different sizes, 4 types of crust, and 12 toppings for his pizza. Which of th
hjlf

Answer:

240

Step-by-step explanation:

5x4x12=240

if you multiply the amount of sizes he can get times the amount of crust sizes he can get you get the pizza it's self (20)

now including the toppings (12) this means 20x12 gets you the amount of toppings on those induviduale pizza's.

Hope this helps!

Brainliest please!

Please fully rate!

Have a great day!

8 0
2 years ago
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The force of gravity on Mars is different than on Earth. The function of the same situation on Mars would be represented by the
sweet-ann [11.9K]

Answer:

If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.

Step-by-step explanation:

Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

v=v_0+a\,*\,t\\y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.

Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

v=v_0+a\,*\,t\\0=v_0-g\,*\,t\\t=\frac{v_0}{t}

When we use this to replace the 't" in the displacement formula, we et:

y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2\\y-y_0=v_0\,(\frac{v_0}{g} )-\frac{g}{2} \,(\frac{v_0}{g} )^2\\y-y_0=\frac{1}{2} \frac{v_0^2}{g}

This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)

And we can also answer the question about time, since given the same initial velocity v_0 , the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)

3 0
3 years ago
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