What is the best approximation for the perimeter of a semicircle with a diameter of 64 meters?

2 answers:

OverLord2011 [107]3 years ago

7 0

By definition, the perimeter of a semicircle is given by:
 $P = ( \pi ) * (r) + d$
 Where,
d: diameter of the semicircle
r: radius of the semicircle.
The radius of the semicircle is given by:
 $r = d / 2 
$
 Where,
d: diameter of the semicircle
Substituting values:
 $r = 64/2 

r = 32 m$ 
Then, the perimeter is:
 $P = (3.14) * (32) + 64 

P = 
 164.48 m$ 
Answer:
The perimeter of the semicurcle is given by:
P = 164.48 m

Natasha_Volkova [10]3 years ago

6 0

Answer: 164.48

Step-by-step explanation:

and don't forget we all have different answers :D

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Let x be a Poisson random variable with μ = 9.5. Find the probabilities for x using the Poisson formula. (Round your answers to

miv72 [106K]

Answer: 1

Step-by-step explanation: the probability mass function that defines a possion probability distribution is given below as

P(x=r) = e^-u × u^x/x!

For this question, x = 0 and u = 9.5

Hence we have that

P(x=0) = e^-0 × 9.5^0 / 0!

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4 years ago

You have measured the systolic blood pressure of a random sample of 25 employees of a company located near you. A 95% confidence

Alla [95]

Answer:

$122 \leq \mu \leq 138$

The 95% confidence interval would be given by (122;138)

And the correct interpretation for this case is:

c. If the procedure were repeated many times, 95% of the resulting confidence intervals would contain the population mean systolic blood pressure.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % where by a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=25-1=24$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,24)".And we see that $t_{\alpha/2}=2.06$