What is the best approximation for the perimeter of a semicircle with a diameter of 64 meters?
2 answers:
<span> By definition, the perimeter of a semicircle is given by:
</span>
<span> Where,
d: diameter of the semicircle
r: radius of the semicircle.
The radius of the semicircle is given by:
</span>
<span> Where,
d: diameter of the semicircle
Substituting values:
</span>
<span>
Then, the perimeter is:
</span>
<span>
Answer:
The perimeter of the semicurcle is given by:
P = </span><span> <span>164.48</span></span> m
</span>
<span> Where,
d: diameter of the semicircle
r: radius of the semicircle.
The radius of the semicircle is given by:
</span>
<span> Where,
d: diameter of the semicircle
Substituting values:
</span>
Then, the perimeter is:
</span>
Answer:
The perimeter of the semicurcle is given by:
P = </span><span> <span>164.48</span></span> m
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The image is missing so i have attached it.
Answer:
Volume = 1.5 litres
Step-by-step explanation:
Using pythagoras theorem, we can get the height (h) of the cylinder
14² + h² = 17²
h² = 289 - 196
h = √93
Now, volume of a cylinder is;
V = πr²h
In the image, r = diameter/2 = 14/2 = 7cm
Thus,
V = π × 7² × √93
V = 1485 cm³
Now, 1 litre = 1000 cm³
Thus, volume = 1485/1000 = 1.485 litres ≈ 1.5 litres
