Answer no 1:
a)
The genotype for parent 1 is GgSs . The phenotype of parent 1 will be Green and short.
The genotype of the second parent is GgSs . The phenotype of the parent 2 is green and short.
b)
The phenotype of the offspring GgSS will be green and short.
The phenotype of the offspring GgSs will be green and short.
The phenotype of the offspring Ggss will be green and long.
The phenotype of the offspring ggSs will be striped and short.
c)
There are four phenotypes in the ratio 9: 3:3: 1
Answer no 2:
Block A:
Genotype; BBHh
Phenotype: Black and long hair
Block B:
Genotype: BbHh
Phenotype : Black and long hair
Block C:
Genotype: Bbhh
Phenotype :Black and short hait
Block D:
Genotype: bbHh
Phenotype :White and long hair
Block E:
Genotype: bbhh
Phenotype : White and short hair
b)
The probability of getting a black horse with short hair is 18.75(19) %
c)
The probability of getting a white horse with long hair is 18.75(19) %
Answer No 3)
1/2 = 50 %
4/16 = 25%
75%= 3/4
1/4 = 25%
Answer No 4:
The first punnet square shows 1/2 grey and 1/2 striped blocks. The percentage will be 50% for grey and 50% for striped.
The ration will be 1:1.
The second punnet square shows 3/4 grey and 1/4 empty blocks. The percentage will be 75% for grey and 25% for striped.
The ratio will be 3:1
You are right with your answer please
The right answer is 5 - 10 seconds.
The heartbeat check according to ACLS should not take more than that.
The steps for checking your heartbeat are:
Have a watch. It will be used to measure your heart rate.Choose a place to take your pulse. It is better to choose either the neck or the wrist.
Place your fingers so that you feel your heartbeat. Choose a duration for the measurement (5 to 10 seconds).
Start counting.
Multiply the number by 12 if you counted for 5 seconds (by 6 if it is 10 seconds).
The normal frequency is between 50 and 80 bpm
C) ball and socket is the answer
