The <em>final temperature </em><em>of the</em><em> water, T2</em> = <em>38.57°C</em>
Temperature can be defined as a measure of the degree of hotness or coldness of a physical object (body). Thus, it is measured with a thermometer and its units are degree Celsius (°C), Fahrenheit (°F) and Kelvin (°K).
A calorie refers to the amount of heat required to raise the temperature of a gram of water by one (1) degree Celsius (1°C).
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<u>Given the following data:</u>
- Quantity of energy = 420J
- Initial temperature, T1 = 10°C
The specific heat capacity of water is 4.2 J/g°C.
To find the final temperature of the water (T2):
Mathematically, the quantity of energy (heat capacity) is given by the formula;

Where;
- Q represents the heat capacity or quantity of heat.
- M represents the mass of an object.
- C represents the specific heat capacity of water.
- dt represents the change in temperature.
Substituting the values into the formula, we have;


Change in temperature, dt = 28.57°C
Next, we would solve for the final temperature by using this formula;


<em>Final temperature, T2 = 38.57°C</em>
<em>Therefore</em><em>, </em><em>the</em><em> final temperature </em><em>of the</em><em> water, T2</em> is equal to <em>38.57°C</em>
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