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3 years ago

What is the molar mass of Sr(OH)2

Chemistry

2 answers:

Anna71 [15]3 years ago

5 0

Answer:

121.63 g/mol

Explanation:

Sr(OH) 2 = Strontium Hydroxide

snow_lady [41]3 years ago

5 0

I believe the answer is 121.63 g/mol

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What are the advantages and disadvantages of living in a group?

Feliz [49]

Advantages
people are there to help
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disadvantages
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3 years ago

A baseball has a mass of 135 grams and a softball has a mass of 270 grams. In which of the following situations would they have

liraira [26]

Answer:

The baseball is thrown twice as fast as the softball in the same direction.

Explanation:

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3 years ago

What is the voltage of the electricity that a washing machine or stove would need in your home?

Zielflug [23.3K]

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1 year ago

The two isotopes of chlorine are LaTeX: \begin{matrix}35\\17\end{matrix}Cl35 17 C l and LaTeX: \begin{matrix}37\\17\end{matrix}C

Kay [80]

Answer: The percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 77.5% and 22.5% respectively.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope be 'x'. So, fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope will be '1 - x'

For $_{17}^{35}\textrm{Cl}$ isotope:

Mass of $_{17}^{35}\textrm{Cl}$ isotope = 35 amu

Fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope = x

For $_{17}^{37}\textrm{Cl}$ isotope:

Mass of $_{17}^{37}\textrm{Cl}$ isotope = 37 amu

Fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope = 1 - x

Average atomic mass of chlorine = 35.45 amu

Putting values in equation 1, we get:

$35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775$

Percentage abundance of $_{17}^{35}\textrm{Cl}$ isotope = $0.775\times 100=77.5\%$

Percentage abundance of $_{17}^{37}\textrm{Cl}$ isotope = $(1-0.775)=0.225\times 100=22.5\%$

Hence, the percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 77.5% and 22.5% respectively.

6 0

3 years ago

Which of the following represents the relative charge of proton

Snowcat [4.5K]

You’ve not put anything below so I’m not sure what the options are but the relative charge of a proton is +1

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2 years ago