The answer is ctually 44
68-2 (3x1)4
68-2x3x4
68-24
44
Let the amount invested with 5% interest be x
Therefore, the amount invested with 6% interest will be (6000-x)
It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:

Multiplying both sides by 100 we get:


Subtracting both sides by 36000 we get:


Thus, the amount invested at 5% is $2250
Therefore, the amount invested at 6% will be $(6000-2250)=$3750
Answer:
m = - 5/4
Step-by-step explanation:
If two lines are perpendicular, their slopes are negative reciprocals, which means that their product is -1
We can write the equation
4*x - 5*y + 13 = 0
as: 5*y = 4*x + 13 or
y = (4/5)*x + 13 (1)
Equation (1) is the equation of a straight line in its slope point form, 4/5 is the slope, according to this the slope of a perpendicular line is
-5/4
Answer:
The daily shop productivity is 480 frames
Step-by-step explanation:
The daily machine productivity refers to the TOTAL production made in a day.
The problem says that a shop produces metal on two different machines. It means that you must take into account the daily production of each one for finding the total production.
The first machine produces 300 frames in a day.
The second machine produces 180 frames in a day too.
So, if the first and the second machines are working together in a single day, the TOTAL daily production is the sum of the production of each one.

Thus, the daily shop productivity is 480 frames
Answer:
The minimum value of f(x) is 2
Step-by-step explanation:
- To find the minimum value of the function f(x), you should find the value of x which has the minimum value of y, so we will use the differentiation to find it
- Differentiate f(x) with respect to x and equate it by 0 to find x, then substitute the value of x in f(x) to find the minimum value of f(x)
∵ f(x) = 2x² - 4x + 4
→ Find f'(x)
∵ f'(x) = 2(2)
- 4(1)
+ 0
∴ f'(x) = 4x - 4
→ Equate f'(x) by 0
∵ f'(x) = 0
∴ 4x - 4 = 0
→ Add 4 to both sides
∵ 4x - 4 + 4 = 0 + 4
∴ 4x = 4
→ Divide both sides by 4
∴ x = 1
→ The minimum value is f(1)
∵ f(1) = 2(1)² - 4(1) + 4
∴ f(1) = 2 - 4 + 4
∴ f(1) = 2
∴ The minimum value of f(x) is 2