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drek231 [11]
3 years ago
5

Controlling the physical world with sensors and digital devices depends on bandwidth and the ability to analyze data in real tim

e. Select one: True False
Computers and Technology
1 answer:
erma4kov [3.2K]3 years ago
5 0

Answer:

The answer is "True".

Explanation:

A sensor is a tool, that senses environmental changes, and reacts to the certain activity of the other machine. It converts a physical event through an analog or sometimes an electronic signal, which is translated or displayed for reading and further analysis.

It also controls the bandwidth and also the ability to analyze information in real-time rely mostly on physical universe monitoring with sensors, that's why it is true.

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3 years ago
Using the FAFSA form , you can for apply for what
AlladinOne [14]

apply for financial aid for college or grad school.

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Read 2 more answers
A network that has locations in different countries is considered a WAN.<br> a. Trueb. False
fiasKO [112]

Answer:

True.

Explanation:

Wide area network (WAN) can be defined as a telecommunication network that covers a wide range of geographical locations such as countries or regions across the world for the purpose of communication and sharing information and data between different users.

Hence, a network that has locations in different countries is considered a wide area network (WAN).

Generally, wide area network (WAN) makes it possible for various organizations to interconnect with their branch offices, headquarters and other multiple locations across the globe. Wide area network (WAN) usually span over a distance of 50 kilometers.

6 0
3 years ago
)What item is at the front of the list after these statements are executed?
Dominik [7]

Answer:

C.Rudy

Explanation:

A deque waitingLine is created.Then Jack is added to front of the deque first.After that Rudy is added to the front of the deque.AFter that Larry and sam are inserted at the back.So the last item inserted at the front is front of the deque.So Rudy was the last item inserted at the front.

Hence we conclude that the answer is Rudy.

4 0
3 years ago
Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a space. Ex: If origList =
Darya [45]

Answer:

#include <stdio.h>

int main(void) {

const int NUM_VALS = 4;

int origList[NUM_VALS];

int offsetAmount[NUM_VALS];

int i;

origList[0] = 20;

origList[1] = 30;

origList[2] = 40;

origList[3] = 50;

offsetAmount[0] = 5;

offsetAmount[1] = 7;

offsetAmount[2] = 3;

offsetAmount[3] = 4;

for(i=0;i<NUM_VALS;i++)

{

printf("%d ",origList[i]+offsetAmount[i]);

}

printf("\n");

return 0;

}

Explanation:

  • Initialize the origList and offsetAmount variables.
  • Loop up to the value of NUM_VALS variable.
  • Display the output by combining origList and offsetAmount.
5 0
2 years ago
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