Draw out a number line. Plot -7 and 12 on the number line. Draw in the tickmarks between them. You should find the distance from -7 to 12 is 19 units since you need to go 19 spaces from either -7 to 12, or vice versa.

You can use subtraction to get

-7-12 = -19

12-(-7) = 12+7 = 19

The final result is made positive since negative distance does not make sense.

So you'd have |-7-12| = |-19| = 19 or |12-(-7)| = |19| = 19.

All of this only works because the two y coordinates are the same, which makes a horizontal line through the two given points.

7 0

3 years ago

Graph the system of inequalities y> 2x-3 and 3y-x≤6

Veronika [31]

Y > 2x - 3
3y - x ≤ 6
   ↓
y = 2x - 3
3y - x = 6

    3(2x - 3) - x = 6
3(2x) - 3(3) - x = 6
      6x - 9 - x = 6
      6x - x - 9 = 6
   5x - 9 = 6
   <u> + 9 + 9</u>
      <u>5x</u> = <u>15</u>
       5      5
      x = 3
y = 2x - 3
y = 2(3) - 3
y = 6 - 3
y = 3
(x, y) = (3, 3)

4 0

3 years ago