
, we know that on Month 0, the Books were 80

we also know that on the first month there were 100 books,

now, how many books when t = 8? A=80(1+0.25)⁸, or A=80(1.25)⁸.
Answer:
A
Step-by-step explanation:
In the graphing calculator, I tried out the different answers, and I think this graph matches yours pretty closely. x is multiplied by a number greater than one, and it looks like instead of expanding/stretching open, it folded in more, which is compressing.
The answer is A because you would do 79 x 0.05 which equals 3.95 . So you subtract 3.95 from 79 which is 75.05 minus 50 equal to 25.05
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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