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3 years ago

7

This diagram is not drawn to scale. Based on the information in the diagram, which of the following statements are true? Select

all that apply.
FG>FH
FG>EH
FE>FG
EH>FG
GH>FG

1 answer:

Lapatulllka [165]3 years ago

3 0

Answer: eh fg

Step-by-step explanation:

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498.4 x 10 to the second power

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Step-by-step explanation:

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3 years ago

√secA+tanA/√secA-tanA × √cosecA-1/√cosecA+1=1

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$Use:\\\\\sec A=\dfrac{1}{\cos A}\\\\\tan A=\dfrac{\sin A}{\cos A}\\\\\csc A=\dfrac{1}{\sin A}\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}\\---------------------------------\\\\\sec A+\tan A=\dfrac{1}{\cos A}+\dfrac{\sin A}{\cos A}=\dfrac{1+\sin A}{\cos A}\\\\\sec A-\tan A=\dfrac{1-\sin A}{\cos A}\\\\\csc A-1=\dfrac{1}{\sin A}-\dfrac{\sin A}{\sin A}=\dfrac{1-\sin A}{\sin A}\\\\\csc A+1=\dfrac{1+\sin A}{\sin A}$

$\dfrac{\sqrt{\sec A+\tan A}}{\sqrt{\sec A-\tan A}}\cdot\dfrac{\sqrt{\cos A-1}}{\sqrt{\cos A+1}}=1\\\\L_s=\sqrt{\dfrac{\sec A+\tan A}{\sec A-\tan A}\cdot\dfrac{\cos A-1}{\cos A+1}}=\sqrt{\dfrac{\frac{1+\sin A}{\cos A}}{\frac{1-\sin A}{\cos A}}\cdot\dfrac{\frac{1-\sin A}{\sin A}}{\frac{1+\sin A}{\sin A}}}\\\\=\sqrt{\dfrac{1+\sin A}{\cos A}\cdot\dfrac{\cos A}{1-\sin A}\cdot\dfrac{1-\sin A}{\sin A}\cdot\dfrac{\sin A}{1+\sin A}}\\\\\text{Everything are simplified}\\\\=\sqrt{1}=1=R_s$

7 0

3 years ago

Help!!! Need Anwser!!!

jolli1 [7]

Hello.

The answer is choice A. angle 1 = 118, angle 2 = 118

Explanation:

The four angles above are congruent (meaning the same) to the ones beneath.

Angles 1 and 2 are also congruent, so they will measure the same.

Lets label the angles above A, B, C, D. B being the known angle, which is 118°. The angles beneath can be labelled E, F, G, H.

∠B ≅ ∠D

∠ABCD ≅ ∠EFGH

∠BD ≅ ∠FH

FH (or 1 and 2) equal 118.

4 0

4 years ago