Answer:
The desired equation is y = (-8/3)x + 26/3.
Step-by-step explanation:
Moving from (1,6) to (4, -2) involves an increase of 3 in x and a decrease of 8 in y. Thus, the slope of the line thru these two points is m = rise / run = -8/3.
Using the slope-intercept form of the eq'n of a straight line and inserting the data given (slope = m = -8/3, x = 4, y = -2), we get:
y = mx + b => -2 = (-8/3)(4) + b, or -2 = -32/3 + b
Multiply all terms by 3 to clear out the fraction:
-6 = -32 + 3b.
Then 26 = 3b, and b = 26/3.
The desired equation is y = (-8/3)x + 26/3.
Answer:
I think its the second one, im not quite sure.
Answer:
(-2, 3)
Step-by-step explanation:
the point B is
B(x,y)
x
AB (A to B) is twice BC ( B to C )
AB is 2 - x. BC is x - (-4)= x + 4
So
2-x=2 (x + 4)
2-x=2x + 8
3x = -6
x = -2
y
(Same logic as above)
AB is -5 -y. BC is u - 7
-5 -y = 2(y - 7)
-5 - y = 2y - 14
3y = 9
y= 3
the point is (-2, 3)
Answer:
d
Step-by-step explanation:
