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Over [174]
3 years ago
9

Test 69,902 for divisibility by 2, 3, 5, 9, or 10.

Mathematics
1 answer:
Keith_Richards [23]3 years ago
5 0
Its only divisible by 2.
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Compare 2x+8>18 and 2x+8 greaterthan or equal to 18
Sergio039 [100]
2x + 8 > 18                      2x+ 8 ≥ 18
2x > 18 -8                            2x ≥ 18 - 8
2x > 10                                 2x ≥ 10
x > 10/2                                  x ≥ 10/2
x>5                                          x ≥ 5

     The answer that combines both inequality is x ≥ 5
6 0
2 years ago
Many do apply pls helpn
Ugo [173]

Answer:

a and b

Step-by-step explanation:

i think b i know a for sho

4 0
3 years ago
Read 2 more answers
Proportions and equations solve
kirza4 [7]
Y=9x because if you divided y by x all the numbers will  equal to 9 which is proportional
7 0
3 years ago
Giovanni purchased 25tickets to an airshow. the cost of an adult's ticket is $14 and the child's ticket is $8. if the total cost
Masteriza [31]

Giovanni purchased 20 adult tickets and 5 child's tickets.

Step-by-step explanation:

Let,

x = Adult tickets

y = Child's tickets

According to given statement;

x+y=25 Eqn 1

One adult ticket costs $14 and one child ticket costs $8, therefore,

14x+8y=320 Eqn 2

Multiplying\ Eqn\ 1\ by\ 8\\8(x+y=25)\\8x+8y=200\ Eqn\ 3\\Subtracting\ Eqn\ 3\ from\ Eqn\ 2\\(14x+8y)-(8x+8y)=320-200\\14x+8y-8x-8y=120\\6x=120\\Dividing\ both\ sides\ by\ 6\\\frac{6x}{6}=\frac{120}{6}\\x=20

Putting value of x in Eqn 1;

20+y=25\\y=25-20\\y=5

Giovanni purchased 20 adult tickets and 5 child's tickets.

Keywords: Linear equations, Addition

Learn more about linear equations at:

  • brainly.com/question/4460262
  • brainly.com/question/4464845

#LearnwithBrainly

6 0
3 years ago
I need help with this please its due today :(
yKpoI14uk [10]

Answer:

a) \ 6^2 \times 6^3 = 6^{2+3} = 6^5 = 7776\\\\b)\ \frac{(-3)^5 }{(-3)^2} = (-3)^{5-2} = (-3)^3 = -27\\\\c)\ [(-2)^3]^4 = (-2)^{3\times 4} = (-2)^{12} = 4096 \\\\d)\ (\frac{1}{999})^0 = 1,  anything \ raise \ to \ zero = 1\\\\e) \ (\frac{4}{3})^{-2} = 4^{-2} \times 3^2 = \frac{9}{16}\\\\f) \ \frac{2^5 \times 2^9}{2^{16}} = 2^{5+9-16} = 2^{-2} = \frac{1}{4}

4 0
3 years ago
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