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torisob [31]
3 years ago
9

The populations and areas of four states are shown. A 3-column table has 4 rows. The first column has entries State A, State B,

State C, State D. The second column is labeled Population with entries 1,055,173, 1,333,089, 3,596,677, 6,745,408. The third column is labeled Area (kilometers squared) with entries 2,677, 36,418, 5,543, 10,555. Which statement regarding these four states is true? The state with the lowest population has the greatest population density. The state with the second lowest population has the lowest population density. The state with the lowest population has the lowest population density. The state with the second greatest population has the lowest population density.
Mathematics
2 answers:
luda_lava [24]3 years ago
7 0

The state with the second lowest population has the lowest population density

dedylja [7]3 years ago
6 0

Answer:

B

Step-by-step explanation:

First, pop. density for State A:

population/area : 1,055,173 / 2,677 = 394.16

For State B:

pop./A : 1,333,089 / 36,418 = 36.61

For State C:

pop.A : 3,596,677 / 5,543 = 648.87

For State D:

pop./A : 6,745,408 / 10,555 = 639.07

Okay!

So with this data, we can easily rule out the first option (State A has the least population, but it isn't the most densely populated). Moving on to the second option, we see that the state with the second-lowest population, State B, also has the lowest population density! Thus, our answer is B (haha which is coincidentally the State name).

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Answer:

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Step-by-step explanation:

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Answer:

x = 7, x = -10

Step-by-step explanation:

x^2+3x-70 = 0

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3 years ago
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3 years ago
Weiming, Joyce and Siti divide cookies to sell in a ratio of 5: 12: 9. After Weiming sold 28 cookies, the ratio becomes 1: 8: 6.
Strike441 [17]

Answer:

216 cookies

Step-by-step explanation:

From the question,

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Total  = 5+12+9 = 26.

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If weiming sold 28 cookies

⇒ (5x/26)-28

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Hence Weiming new share = (5x-728)/28 cookies

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The total cookies becomes = x-28

Therefore,

(1/15)(x-28) = (5x-728)/28

(x-28)/15 = (5x-728)/28

Crossmultiply

28(x-28) = 15(5x-728)

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28x-75x = -10920+784

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8 0
3 years ago
33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

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Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

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which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
3 years ago
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