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Murljashka [212]
3 years ago
5

Bracket is necessary in order of operations​

Mathematics
2 answers:
Makovka662 [10]3 years ago
5 0

Answer:

yes

Step-by-step explanation:

they are necessary

dexar [7]3 years ago
5 0

Answer:

yeah they are necessary in fact they are the first when you use BODMAS

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Please help me I will reward brainlest
nikklg [1K]

C, the sum of the decimals is greater than one, meaning they shade more than one.

4 0
3 years ago
Read 2 more answers
Solve the equations.<br> a. (x − 2)^2 = 9<br> b. 3(x − 2)^2 = 9<br> c. 6 = 24(x + 1)^2
seropon [69]

Answer: a) x = 5 or -1 b) x = √3+2

c) x = -1/2 or -3/2

Step-by-step explanation:

a) (x − 2)² = 9

First step is to take the square root of both sides to eliminate the square

√ (x − 2)² = √9

x-2 = +-3

x = +3+2

x = 5 and;

x = -3+2

x = -1

x = 5 or -1

b) 3(x-2)² = 9

First we divide both sides by 3 to get;

(x-2)² = 9/3

(x-2)² = 3

Second step is to take the square root of both sides to eliminate the square

√(x-2)² = √3

x-2 = √3

x = √3+2

c) 6 = 24(x+1)²

Dividing both sides by 24, we have

6/24 = (x+1)²

1/4 = (x+1)²

Taking the square root of both sides we have

√1/4 = √(x+1)²

= +-1/2 = x+1

x = +1/2-1 = -1/2 and;

x = -1/2-1 = -3/2

x = -1/2 or -3/2

4 0
3 years ago
If you invest $823 at an interest rate of 3 percent,how much money will you have in total afer nine years?​
valentinak56 [21]

Answer:

$1,045.21

Step-by-step explanation:

7 0
3 years ago
The sum of two polynomials is –yz2 – 3z2 – 4y + 4. If one of the polynomials is y – 4yz2 – 3, what is the other polynomial? –2yz
marishachu [46]

The first polynomial is y -4yz^2-3 and let the second polynomial be P(y,z).

If the sum of two polynomials is -yz^2-3z^2-4y+4, then y-4yz^2-3+P(y,z)=-yz^2-3z^2-4y+4.

Take the first polynomial from the left side to the right side:

P(y,z)=-yz^2-3z^2-4y+4 -(y-4yz^2-3),\\ P(y,z)=-yz^2-3z^2-4y+4 -y+4yz^2+3,\\ P(y,z)=3yz^2-3z^2-5y+7.

Answer: the second polynomial is 3yz^2-3z^2-5y+7.

3 0
3 years ago
Read 2 more answers
Select the expressions that are equivalent to 12n - 8. Select all that apply.
morpeh [17]

A.3n+4+3n+4+4n

=3n+3n+4n+4+4

=10n+8

B.11n+4+n-12

=11n+n+4-12

=12n-8

C.6(6n-2)

=36n-12

D.4(3n-2)

=12n-8

E.4n+22-12+8n

=4n+8n+22-12

=12n+10

so,B and D are the expressions that are equivalent to 12n-8.

3 0
2 years ago
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