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yuradex [85]
3 years ago
15

Solve the equation

e=" \frac{3}{8}x - 17 = 10" alt=" \frac{3}{8}x - 17 = 10" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Annette [7]3 years ago
5 0

Answer:

x = 72

Step-by-step explanation:

<u>To solve for 'x', isolate it</u>. This means to keep 'x' on one side of the equal sign, while moving the other numbers to the other side. The numbers on the other side will tell you what 'x' equals to.

<u>When 'moving' a number to the other side, you cancel it out where it originally is by doing reverse operations</u>. (Reverse operation pairs are addition/subtraction and division/multiplication). To keep an equation balanced, <u>what you do to one side you have to do to the other</u>.

\frac{3}{8}x-17=10        Keep 'x' on the left and move everything over.

\frac{3}{8}x-17+17=10+17        Add 17 to both sides. "-17" cancels out on the left.

\frac{3}{8}x=27        Simplified right side

\frac{3}{8}x/\frac{3}{8}=27/\frac{3}{8}        Because 3/8 originally multiplies with 'x', do the reverse: divide both sides by 3/8.

x=27/\frac{3}{8}        To divide a fraction, change to multiplication and flip the fraction's top and bottom numbers.

x=27*\frac{8}{3}        Combine the factors into one fraction.

x=\frac{27*8}{3}        Multiply 27 by 8 in the numerator.

x=\frac{216}{3}        Simplify the fraction by dividing top by bottom.

x=72        Final answer, solved for 'x'

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o-na [289]

Answer:

a) n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401  

And rounded up we have that n=2401

b) n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22  

And rounded up we have that n=626

And we see that if we have previous info about p the sample size varies a lot.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

Part a

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Since we don't have prior information about the population proportion we can use ase estimator \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401  

And rounded up we have that n=2401

Part b

For thi case the estimator for p is \hat p =0.07

n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22  

And rounded up we have that n=626

And we see that if we have previous info about p the sample size varies a lot.

4 0
3 years ago
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