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3 years ago

Numbers on the y-axis increase in which direction on a coordinate plane?

Mathematics

1 answer:

dalvyx [7]3 years ago

4 0

Numbers on the y-axis on a coordinate plane increase in UP direction.

Left hand side is '-x', right hand side is 'x'

Up is 'y' and down is '-y'

Y is the vertical axis and X is horizontal axis.

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Rewrite 3x+5y=11 and -5x+7y=9 in slope intercept form

chubhunter [2.5K]

Problem 1

subtract 3 x

5y=-3x+11

divide 5

y=3/5x+2.2'

Problem 2

add 5x

7y=5x+9

divide 7

y=5/7x+1.3'

'notice'

you can put 2.2 into a fraction (11/5) and 1.3 (9/7) if your teacher allows it, but i put them into decimals

4 0

2 years ago

Sal pitched 15 games. If Sal pitched 3 out of 5 games his team played, how many games did his team play?

fiasKO [112]

Answer:

As we know he pinched 15 games and he pitched 3/5, we can do a rule of three:

15 - 3/5

x 1

We out a 1 ad that's the total, 5//5

So now we know x = , = 25

He pitched 25 games

7 0

3 years ago

Question 4, plz help ( radius is 6.8)

Kisachek [45]

Answer:

A) 145.3 cm^2

Step-by-step explanation:

The formula for the area of a circle is A = π r^2

So to find the area we would plug the radius of 6.8 into the formula

Area = π (6.8)^2

Area = (3.14) (6.8)^2

Area = 145.27

Area = 145.3

4 0

2 years ago

3x•(7•x) ASAP PLEASE

NeX [460]

Answer:

21 x ^2

Step-by-step explanation:

3x(7x)

=3*x*7*x

=21*x^2

=21x^2

7 0

2 years ago

Solve this trigonometry question too, please by an easy method.

Anton [14]

Answer:

proof given below

Step-by-step explanation:

Combine the fractions by making the denominators the same:

$\dfrac{\sin \theta}{1+ \cos \theta}+\dfrac{1+ \cos \theta}{ \sin \theta}$

$=\dfrac{\sin \theta}{1+ \cos \theta} \cdot \dfrac{\sin \theta}{\sin \theta}+\dfrac{1+ \cos \theta}{ \sin \theta} \cdot \dfrac{1+ \cos \theta}{1+ \cos \theta}$

$=\dfrac{\sin \theta(\sin \theta)}{\sin \theta(1+ \cos \theta)}+\dfrac{(1+ \cos \theta)(1+ \cos \theta)}{\sin \theta(1+ \cos \theta)}$

$= \dfrac{\sin^2 \theta}{\sin \theta(1+ \cos \theta)} +\dfrac{1+2 \cos \theta + \cos^2 \theta}{\sin \theta(1+ \cos \theta)}$

$= \dfrac{\sin^2 \theta+ \cos^2 \theta+1+2 \cos \theta }{\sin \theta(1+ \cos \theta)}$

Use the trigonometric identity $\sin^2 \theta + \cos^2 \theta=1$ :

$= \dfrac{1+1+2 \cos \theta}{\sin \theta(1+ \cos \theta)}$

$= \dfrac{2+2 \cos \theta}{\sin \theta(1+ \cos \theta)}$

Factor out 2 from the numerator:

$= \dfrac{2(1+ \cos \theta)}{\sin \theta(1+ \cos \theta)}$

Cancel the common factor:

$= \dfrac{2}{\sin \theta}$

$\textsf{Use the identity} \quad\csc \theta=\dfrac{1}{\sin \theta}:$

$=2 \csc \theta$

Hence proved.

Learn more about trigonometric identities here:

brainly.com/question/27938536

3 0

2 years ago