The distance covered by the hare and the tortoise in t seconds are 8t and 5t respectively. (Simple Speed-Distance-Time relation)
The tortoise gets a 510m headstart so at t=0 is 1490m.
The functions representing the distance of both of them from the finish line is,
F(x)=2000-8t,. for hare
G(x)=1490-5t,. for tortoise
Answer:
GCD=11
Step-by-step explanation:
Factors of 2563 are: 1 , 11 , 233 , 2563.
Factors of 4147 are: 1 , 11 , 13 , 29 , 143 , 319 , 377 , 4147.
Answer:
2(x+10) = 3x-30 (reason: vertical angles are congruent)
2x+20 = 3x-30
20 = 1x-30
1x = 20+30
1x = 50
x = 50
Answer:
Step-by-step explanation:
x² + 4x - 1 - x =x² + 4x -x - 1 { bring the like terms together and add}
= x² + 3x - 1
