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Alla [95]
3 years ago
6

6x+3y=12 in slope-intercept form

Mathematics
1 answer:
shepuryov [24]3 years ago
7 0

Answer:

Slope: −2-2

y-intercept: (0,4)

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Which unit price is the highest? turnips for $1.51 per pound peppers for $1.62 per pound parrots for $1.26 per pound celery for
Rom4ik [11]

Answer:

The highest price is of peppers $1.62

Step-by-step explanation:

Cost of turnips per pound = $1.51

Cost of peppers per pound = $1.62

Cost of the carrots per pound = $1.26

Cost of celery per pound = $1.48

As all the costs are given in the same unit prices, we can simply compare the prices to find out  highest value.

The highest price is of peppers $1.62.

7 0
3 years ago
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Find the constant of variation for the relationship f(x)= 30x.
trasher [3.6K]
For a direct variation, f(x) = kx. Therefore, for f(x) = 30x, constant of variation (k) = 30.
3 0
3 years ago
Read 2 more answers
PLEASE HELP ME IN MATH
maks197457 [2]

Answer:

BC= 23.0km (nearest tenth)

Step-by-step explanation:

Please see the attached picture for full solution.

6 0
3 years ago
An endurance athlete jogs at a rate of 8 miles per hour. How many minutes does it take for the athlete to jog 2.4 miles?
Vika [28.1K]

Answer:

0.3

Step-by-step explanation:

7 0
3 years ago
The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
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