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emmasim [6.3K]
3 years ago
11

I need help please.......

Mathematics
1 answer:
exis [7]3 years ago
5 0
He worked for 12 days. 12 x 2 = 24
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The recursive formula for an arithmetic sequence is an = an - 1 + d.
LekaFEV [45]
If an is a5
and
an-1 is a4

then using your recursive formula for an arithmetic sequence
an=an-1 +d
then
a5=a4+d

now, a4 =6 and common difference "d"  is d=-11
hence
a5=6 -11
6-11= -5


any questions?



3 0
3 years ago
Read 2 more answers
Can anybody explain how to subtract mixed fractions?
Ilya [14]

Answer:

  • <em>convert </em>the mixed fractions to improper fractions (where the numerator is greater than or equal to the denominator): multiply the whole number part by the fraction's denominator, add that to the numerator, write the result on top of the denominator.
  • if the denominators are not the same, work out the common denominator and <em>rewrite </em>the fractions with the same denominators
  • subtract by subtracting the numerators and writing the result over the denominator
  • convert back to mixed fractions by dividing the numerator by the denominator, write down the whole number answer, write down the remainder above the denominator.

Example

3\frac23-1\frac45

convert to improper fractions:

\dfrac{3 \times 3+2}{3}-\dfrac{1 \times 5+4}{5}=\dfrac{11}{3}-\dfrac{9}{5}

common denominator = 3 × 5 = 15, so:

\dfrac{11}{3}-\dfrac{9}{5}=\dfrac{11\times 5}{3\times 5}-\dfrac{9\times 3}{5\times 3}=\dfrac{55}{15}-\dfrac{27}{15}

subtract:

\dfrac{55}{15}-\dfrac{27}{15}=\dfrac{55-27}{15}=\dfrac{28}{15}

convert back to mixed fractions:

28 \div 15=1 \textsf{ remainder }13=1 \frac{13}{15}

7 0
2 years ago
Read 2 more answers
Одна зі сторін прямокутника в 11 разів менша від другої. Знайдіть
Ratling [72]

Answer:

for the plug-in settings to determine

Step-by-step explanation:

GG from Shahs of sunset Blvd suite is the best way to the answer to the answer to the answer to the plug-in the plug-in the whole thing is I don't have a email the e I m not sure if you have any questions or concerns please visit the plug-in settings to determine

5 0
1 year ago
What would be the image of Point B(3, 2) after the following transformations have been applied:
Ulleksa [173]

Answer:

(9,6)

Step-by-step explanation:

(6,9)

Because the scale factor is 3 so u r suppose to multiply by 3

6 0
2 years ago
Read 2 more answers
Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)
DENIUS [597]

Compute the necessary values/derivatives of f(x) at x=1:

f(1)=3

f'(1)=2

f''(1)=-12

f'''(1)=-12

f^{(4)}(1)=48

f^{(5)}(1)=120

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) f(x) at x=1 by

T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5

T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5

###

Another way of doing this would be to solve for the coefficients a,b,c,d,e,g in

f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5

by expanding the right hand side and matching up terms with the same power of x.

5 0
2 years ago
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