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3 years ago

Point slope form through (4,2) slope =7/4

Mathematics

1 answer:

ad-work [718]3 years ago

6 0

The point-slope form:

$y-y_1=m(x-x_1)$

We have the point (4, 2) and the slope m = 7/4. Substitute:

$\boxed{y-2=\dfrac{7}{4}(x-4)}$

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Angles in circle solve for each variable

lisabon 2012 [21]

Answer:

Step-by-step explanation:

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3 years ago

I need help anybody ?

nasty-shy [4]

Answer and Step-by-step explanation:

Simply use the Pythagorean Theorem to solve.

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$A^{2} +B^{2}= C^{2}$

Plug the sides values into the equation.

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3 years ago

What is 4-2x+8+5x simplified

sveta [45]

Answer: it is 3 • (x + 4)

Step-by-step explanation: We move all terms to the left:

4-2x+8-(+5x)=0

We add all the numbers together, and all the variables

-2x-(+5x)+12=0

We get rid of parentheses

-2x-5x+12=0

We add all the numbers together, and all the variables

-7x+12=0

We move all terms containing x to the left, all other terms to the right

-7x=-12

x=-12/-7

x=1+5/7We move all terms to the left:

4-2x+8-(+5x)=0

We add all the numbers together, and all the variables

-2x-(+5x)+12=0

We get rid of parentheses

-2x-5x+12=0

We add all the numbers together, and all the variables

-7x+12=0

We move all terms containing x to the left, all other terms to the right

-7x=-12

x=-12/-7

x=1+5/7

6 0

3 years ago

Read 2 more answers

Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

8 0

3 years ago

A paper popcorn cone measures 4 inches in a diameter and is 9 inches high?

Aloiza [94]

Explanation is in the file

tinyurl.com/wtjfavyw

8 0

3 years ago

Read 2 more answers