Answer:
A. x < 6 and x > - 28
Step-by-step explanation:
We have been given the following inequality;
| x+11 | < 17
We can replace the absolute value function by re-writing the inequality as;
-17< x+11<17
subtract 11 from both sides;
-17-11<x+11-11<17-11
-28<x<6
splitting this we have;
x<6
x>-28
Answer:
The answer is C
Step-by-step explanation:
That side with the 5 is equal to 7.071067812.... (irrational number)
To get x you need to use the equation a^2 + b^2 = c^2
A^2 and B^2 will both be the same thing. The red line indicates they are the exact same length.
7.071037812.... ^2 is 50
Now your equation would be 50+50= c^2 (which is the same as x^2)
100= c^2 is simplified by finding the square root of 100.
Your answer is 10 for side X because the square root of 100 is 10.
This problem was solved using the Pythagorean Theorem.
Given that average mass of an ant 
grams.
Given that average mass of a giraffe 
Kilograms.
Now we have to find about how many times more mass does a giraffe have than an ant. Before carring out any comparision, we must make both units equal.
Like convert kilogram into gram or gram into kilogram.
I'm going to convert kilogram into gram using formula
1 Kg = 1000 g
So the average mass of a giraffe 
grams.
Now we just need to divide mass of giraffe by mass of ant to find the answer.
=666666666.667
Hence final answer is 
which is approx 666666666.667.
Hi, the answer will be 0.5. Hope this helped :).
Answer:
The polynomial with real coefficients having zeros 2 and 2 - 2i is
x³ - 6x² + 16x - 16 = 0
Step-by-step explanation:
Given that a polynomial has zeros at 2 and 2 - 2i, we want to write this polynomial.
We have
x - 2 = 0
x - (2 - 2i) = 0
=> x - 2 + 2i = 0
Since the polynomial has real coefficients, and 2 - 2i is a zero of the polynomial, the conjugate of 2 - 2i, which is 2 + 2i is also a polynomial.
x - (2 + 2i) = 0
=> x - 2 - 2i = 0
Now,
P(x) = (x - 2)(x - 2 + 2i)(x - 2 - 2i) = 0
= (x - 2)((x - 2)² - (2i)²) = 0
= (x - 2)(x² - 4x + 8) = 0
= x³ - 4x² + 8x - 2x² + 8x - 16 = 0
= x³ - 6x² + 16x - 16 = 0
This is the polynomial required.
