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ad-work [718]
3 years ago
13

If the area of an equilateral triangle is 9root3 cm square find its side​

Mathematics
1 answer:
kobusy [5.1K]3 years ago
7 0

Answer:

6 cms.

Step-by-step explanation:

If the side of an equilateral triangle is 2x cm then its height is  √3x and its base is 2x.

Area = 1/2 * base * height

9√3 = 1/2 * 2x * √3x    

9√3 = x * √3x

9 = x^2

x = 3

So length of each side = 2*3 = 6.

x = 9

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Which expression is equivalent to 4r2/514.3V5r8, if x=0?
san4es73 [151]

Step-by-step explanation:

I think it would be c if not D

8 0
3 years ago
59-(2c+3)=4(c+7)+c.
alisha [4.7K]

Step-by-step explanation:

{:}\leadsto\sf 59-(2c+3)=4 (c+7)+c

{:}\leadsto\sf 59-2c-3=4c+28+c

{:}\leadsto\sf 56-2c=5c+28

{:}\leadsto\sf 5c+28=56-2c

{:}\leadsto\sf 5c+2c=56-28

{:}\leadsto\sf 7c=28

{:}\leadsto\sf c={\dfrac {28}{7}}

{:}\leadsto\sf c=4

4 0
3 years ago
Read 2 more answers
Answer and show all of your work.
quester [9]

Answer:

105 shifts

Step-by-step explanation:

Hourly net rate of pay = $12

1 shift = 8 hours

⇒ net pay per shift = $12 × 8 = $96

Total cost  = tuition + residence + books

                  = $4500 + $4800 + $700

                  = $10,000

To calculate how many shifts Joanne needs to work, divide the total cost by the pay per shift and round it up:

Number of shifts = total cost ÷ net pay per shift

                            = $10,000 ÷ $96

                            = 104.1666666...

                            = 105 shifts

<u>Note</u>: we need to round up, as if Joanne works 104 shifts, she will earn $9,984 which is not quite enough to pay for tuition, residence and books.

3 0
2 years ago
Read 2 more answers
Simplified fraction of 49 out of 112
SVETLANKA909090 [29]
The simplified fraction of 49\112 is 7/16. This results from you finding a common number which can divide into 49 and 112 equally. In this case the number is 7. Resulting in the answer 7/16.
7 0
3 years ago
Read 2 more answers
3. Segment GE is an angle bisector of both
777dan777 [17]

ΔHGE and ΔFGE are congruent by the Angle-Side-Angle Congruence Theorem (ASA).

<em><u>Recall:</u></em>

  • A segment that divides an angle into equal parts is known as an angle bisector.
  • Two triangles are congruent by the ASA Congruence Theorem if they share a common side and have two pairs of congruent angles.

In the diagram given, Angle bisector, GE, divides ∠HEF into congruent angles,  ∠HEG ≅ ∠GEF.

Also divides ∠FGH into congruent angles, ∠HGE ≅ ∠FGE.

Both triangles also share a common side, GE

<em>This implies that: ΔHGE and ΔFGE have:</em>

two pairs of congruent angles - ∠HEG ≅ ∠GEF and ∠HGE ≅ ∠FGE

a shared side - GE

Therefore, ΔHGE and ΔFGE are congruent by the Angle-Side-Angle Congruence Theorem (ASA).

Learn more about ASA Congruence Theorem on:

brainly.com/question/82493

4 0
2 years ago
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