(1/2)^2 = 1/4
2-2/3 = 6/3 - 2/3 = 4/3
OK so:
(1/2)^2 - 6(2-2/3) = 1/4 - 6(4/3)
= 1/4 - 8
= 1/4 - 32/4
= -31/4
Answer:
y = 8/5x
Step-by-step explanation:
I'm assuming that they're asking for the equation in point-slope form.
The formula is y=mx+b where:
m = slope
b = y intercept
However, the y intercept is just (0,0) so b = 0
To find the slope we already have 2 given points: (0,0) and (5,8)
To find slope you do rise/run and you get 8/5
Substitute the slope & y intercept in the formula:
y = 8/5x
Let me know if I'm wrong!!
Answer:
y = -2
Step-by-step explanation:
The horizontal line through this point has a slop of 0
This problem can be represented through the following equation
A = A₀(1/2)^t/h
where
A-----------> is the amount of substance left after time t
A₀ ----------> is the original amount---------> 2 g
h-------------> is the half-life-----------> 8 days
for A=0.04 g
t=?
0.04 = 2(1/2)^t/8
0.02 = (1/2)^t/8
Take ln on both sides:
ln(0.02) = ln [(1/2)^t/8]
ln(0.02) = (t/8)(ln 1/2)
t = 8*ln(0.02)/ln(1/2)
t = 45.15 days
the answer is 45.15 days
