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xeze [42]
3 years ago
15

5x to the 3rd power y+35x to the 2nd power y+50xy=

Mathematics
1 answer:
AveGali [126]3 years ago
6 0

5x^3y+35x^2y+50xy=(5xy)(x^2)+(5xy)(7x)+(5xy)(10)\\\\=5xy(x^2+7x+10)=5xy(x^2+5x+2x+10)\\\\=5xy[x(x+5)+2(x+5)]=5xy(x+5)(x+2)

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Factor the following:<br><br><br><br> 2x2+9x+9
ryzh [129]

Answer: (2x+3)(x+3)

Step-by-step explanation:

Looking at this, you know that it must look something like

(? +3)(?+3) , because they must multiply to 9. The ?s must multiply to 2x^2, the most plausible values being 2x and x, ending us up with (2x+3)(x+3)

8 0
2 years ago
Read 2 more answers
Equation of the graph
natka813 [3]

Answer:

A and C

Step-by-step explanation:

It can not be D, since that will mean that <em>the line is perfectly horizontal</em>, with 0 as its slope.

It can be C, since the <em>equation's slope is positive and has a negative y-intercept</em>, like the graph.

Changing around A gives us y = 2x - 3. That has a <em>positive slope and a negative y-intercept</em>, like the graph. So, A is a possibility.

Changing around B gives us y = ²/₃x + 3. This has a positive slope, <em>but also a positive y-intercept</em>, so B can not be the answer.

4 0
3 years ago
Jen Butler has been pricing​ Speed-Pass train fares for a group trip to New York. Three adults and four children must pay $ 79.
xxMikexx [17]

<u>Answer:</u>

Price of the​ adult's ticket = $13

Price of a​ child's ticket = $ 10

<u>Step-by-step explanation:</u>

Given:

Cost of train fares for Three adults and four children = $79

Cost of train fares Two adults and three children  = $ 56

To Find:

Price of the​ adult's ticket and the price of a​ child's ticket =?

Solution:

Let the cost of one adult's ticket be x  and

Let the cost of one child's ticket be y

Then

Three adults and four children must pay $ 79 be

3x + 4y = 79-----------------------------------------------(1)

Two adults and three children must pay $56

2x + 3y = 56----------------------------------------------(2)

multiply  eq(1) by 2, we get

6x + 8y = 158----------------------(3)

multiply  eq(2) by 3, we get

6x + 9y = 168----------------------(4)

Subracting (3) from (4)

 6x + 9y = 168

 6x + 8y = 158

(-)      (-)       (-)

------------------------------

0x +  y = 10

------------------------------

y=10

Now substitute the value of y in eq (1) to get the value of x

3x + 4(10)= 79

3x +  40 = 79

3x = 79 - 40

3x = 39

x = \frac{39}{3}

x= 13

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3 years ago
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