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Zielflug [23.3K]

2 years ago

15

A spinner with 5 equal section labeled 1-5 is spun 50 times. The results are shown in the table below. What is the theoretical p

robability of spinning an even number

1 answer:

bekas [8.4K]2 years ago

5 0

Answer:

18/50

Step-by-step explanation:

The spinner was spun 50 times and both 2 and 4 are even numbers which was landed on 8 and 10 time so therefore 18/50

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A right rectangular prism has edges of 8 feet, 4 feet, and 1/2 foot. How many cubes with side lengths of 1/2 foot would be neede

Ksenya-84 [330]

Answer:

Step-by-step explanation:

From the question we are told that

Edges of 8 feet, 4 feet, and 1/2 foot

Generally the volume V_p of the right rectangular prism is mathematically represented as

$V_p=8*4*0.5$

$V_p=16$

Generally volume of the cube V_c is mathematically given as

$V_c =(\frac{1}{2})^3$

$V_c =\frac{1}{6}$

Therefore total number of cubes is given as

$V=\frac{V_p}{V_c}$

$V=\frac{16}{\frac{1}{6}}$

$V=96$

4 0

3 years ago

Determine the equation

sergejj [24]

Answer:

$y=\frac{3}{4} x-\frac{5}{4}$

Step-by-step explanation:

two points on the line are

(-1, -2)

(-5, -5)

The slope:

$m=\frac{-2-(-5)}{-1-(-5)} =\frac{-2+5}{-1+5} =\frac{3}{4}$

The equation:

with (-1,-2)

$y-(-2)=\frac{3}{4} (x-(-1))$

$y+2=\frac{3}{4} x+\frac{3}{4}$

$y=\frac{3}{4} x+\frac{3}{4} -\frac{8}{4}$

$y=\frac{3}{4} x-\frac{5}{4}$

Hope this helps

8 0

2 years ago

Determine the volume in litres of 14kg of petrol of density 700kg/m³

valkas [14]

Answer:

$p = \frac{m}{v}$

Step-by-step explanation:

Density is the ratio of an object's mass to its volume, and it measures how compact an object is. The density of an object, p, is directly proportional to its mass, m, and inversely proportional to its volume, V:

$p = \frac{m}{v}$

4 0

1 year ago

This one too, again if you dunno it don’t anwser xd

Kobotan [32]

Answer:11

Step-by-step explanation: think about 5+6 then when you add 11 to the -5 you get 6.

4 0

2 years ago

Read 2 more answers

What is the equation process to this question?

Andreyy89

The given equation is $h(t)=-16t^2+80t+4$ where h is the height, in feet, of a ball and t is the time, in seconds.

<u>Part a: The height of the ball when t = 2 seconds:</u>

The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(2)=-16(2)^2+80(2)+4$

Simplifying the terms, we get;

$h(2)=-64+160+4$

$h(2)=100$

Thus, the height of the ball after 2 seconds is 100 feet.

<u>Part b: The height of the ball when t = 4 seconds:</u>

The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(4)=-16(4)^2+80(4)+4$

Simplifying the terms, we get;

$h(4)=-256+320+4$

$h(4)=68$

Thus, the height of the ball after 4 seconds is 68 feet.

5 0

3 years ago