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Thepotemich [5.8K]
3 years ago
15

Spinner goes 1-4. Jose spins the spinner 8 times. In those 8 spins, the arrow never lands on 3. Based on this information, shoul

d Jose be concerned that the spinner is unfair? Explain.
Mathematics
2 answers:
Mademuasel [1]3 years ago
5 0
If the spinner was fair, the probability of landing on 3 in a single spin is 1/4. The probability of never landing on 3 in 8 spins is (3/4)^8 = 0.1. The probability of landing on 3 at least once in 8 spins is 1 - 0.1 = 0.9.
Therefore Jose should be concerned that the spinner is unfair.
Alenkinab [10]3 years ago
3 0
Well this is a more complicated question than it may seem. The laws of probability are based on observations whose number is very large or actually as the number of observations approaches infinity. So on the one hand, you should be concerned that you get 0/8 to land on 3. However, 42/500 land on 3 so your ratio has improved. It's not near 125 but it's also not 0. If it remained at 0, you would begin to be concerned and rightly so. Perhaps if you did 5000, you would be less concerned as the ratio improved and got closer to 1/4 of the observations. So at this point I don't think you have enough information to determine that the spinner is unfair.
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MakcuM [25]

Answer:

     \large\boxed{\large\boxed{47unit^2}}

Explanation:

The complete question is:

<em>A hole the size of a photograph is cut from a red piece of paper to use in a picture frame.</em>

<em />

<em>On a coordinate plane, 2 squares are shown. The photograph has points (-3, -2), (- 2, 2), (2, 1), and (1, -3). The red paper has points (- 4, 4), (4, 4), (4, -4), and (-4, -4).</em>

<em />

<em>What is the area of the piece of red paper after the hole for the photograph has been cut?</em>

<em />

<h2><em>Solution</em></h2>

<em />

The area of the piece of redpaper after the hole has been cut is equal to the area of the big square less the area of the small rectangle.

<u>1. Area of the big rectangle</u>

Vertices:

  • <em>(- 4, 4) </em>
  • <em>(4, 4)</em>
  • <em>(4, -4)</em>
  • <em>(-4, -4)</em>

<em />

The side length is the distance between two consecutive vertices:

The two points (-4,4) and (4,4) has the same y-coordinate, thus the length is just the absolute value of the difference of the x-coordinates:

  • 4-(-4)=4+4=8

The area of this square is    (8unit)^2=64unit^2

<u>2. Area of the small square</u>

Vertices:

  • <em>(-3, -2)</em>
  • <em>(- 2, 2) </em>
  • <em>(2, 1)</em>
  • <em>(1, -3)</em>

<em />

To find the side length use the distance formula for two consecutive points, for instance (2,1) and (-2,2):

      d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\ \\d=\sqrt{(2-(-2))^2+(2-1)^2}=\sqrt{4^2+1^2}=\sqrt{17}

The area is:

          (\sqrt{17}unit)^2}=17unit^2

<u>3. Area of the piece of red paper after the holw for the photograph has been cut:</u>

<u />

Find the difference:

<u />

         64unit^2-17unit^2=47unit^2

<em />

7 0
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Answer:

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Step-by-step explanation:

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Answer:

D. x = 5

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